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Five positive integers, a<=b<=c<=d<=e. If the [#permalink]
 09 Mar 2008, 10:06
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Five positive integers, a<=b<=c<=d<=e. If the median is 40, and the average is 50, what is the least possible value of the largest number?
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Current Student
Joined: 28 Dec 2004
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Location: New York City
Schools: Wharton'11 HBS'12
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Re: PS (least value) [#permalink]
09 Mar 2008, 10:22
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well the sum of all the five integers must be 250..
we know that C is 40..
so assume a=b=c=40 then in that case D and E should be (250-120)=130, if D=E then you get D=E=65
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Re: PS (least value) [#permalink]
09 Mar 2008, 14:05
fresinha12, correct. OA is 65.
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Re: PS (least value)
[#permalink]
09 Mar 2008, 14:05
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