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# Five women bought dresses in a store for an average price of

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Manager
Joined: 25 Feb 2008
Posts: 53
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Five women bought dresses in a store for an average price of [#permalink]

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03 Mar 2008, 05:54
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Five women bought dresses in a store for an average price of $96 each. A sixth woman bought a dress for$30 more than the average of all six. How much did she pay

A) 276
B) 132
C) 126
D) 102
E) 101

I would appreciate answer with explaination.
Thanks
Director
Joined: 01 Jan 2008
Posts: 629
Followers: 4

Kudos [?]: 175 [0], given: 1

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03 Mar 2008, 08:10
Capthan wrote:
Five women bought dresses in a store for an average price of $96 each. A sixth woman bought a dress for$30 more than the average of all six. How much did she pay

A) 276
B) 132
C) 126
D) 102
E) 101

I would appreciate answer with explaination.
Thanks

x - price of dress #6 -> average = (x+5*96)/6 = x - 30 -> x*(5/6)=5*96/6+30 -> x = 96+30*6/5=96+36=132 -> B
Manager
Joined: 05 Feb 2007
Posts: 140
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Kudos [?]: 8 [1] , given: 7

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03 Mar 2008, 08:21
1
KUDOS
I have something different. I got D (102).

96=x/5
x= 480

480+A+30/6 = A
510+A/6=A
A=102
SVP
Joined: 28 Dec 2005
Posts: 1575
Followers: 3

Kudos [?]: 147 [1] , given: 2

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03 Mar 2008, 08:34
1
KUDOS
132.

102 is the average price, question says that the 6th woman paid $30 more than the average, so we have 102+30=132 Manager Joined: 05 Feb 2007 Posts: 140 Followers: 1 Kudos [?]: 8 [0], given: 7 Re: Please help me on this one. average [#permalink] ### Show Tags 03 Mar 2008, 09:51 pmenon wrote: 132. 102 is the average price, question says that the 6th woman paid$30 more than the average, so we have 102+30=132

ah, your right...i didn't quite finish the prob
CEO
Joined: 29 Mar 2007
Posts: 2583
Followers: 19

Kudos [?]: 421 [1] , given: 0

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04 Mar 2008, 08:27
1
KUDOS
Capthan wrote:
Five women bought dresses in a store for an average price of $96 each. A sixth woman bought a dress for$30 more than the average of all six. How much did she pay

A) 276
B) 132
C) 126
D) 102
E) 101

I would appreciate answer with explaination.
Thanks

Original sum : 5*96=480. Now the 6th's womens dress is x.

new avg: (480+x)/6=z we know x=z+30. now its (480+z+30)/6=6z. Just solve.

Now we want X so 102+30 = 132

B
VP
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04 Mar 2008, 19:38
maratikus wrote:
Capthan wrote:
Five women bought dresses in a store for an average price of $96 each. A sixth woman bought a dress for$30 more than the average of all six. How much did she pay

A) 276
B) 132
C) 126
D) 102
E) 101

I would appreciate answer with explaination.
Thanks

x - price of dress #6 -> average = (x+5*96)/6 = x - 30 -> x*(5/6)=5*96/6+30 -> x = 96+30*6/5=96+36=132 -> B

Got B with the same approach
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