Florist 2azaleas, 3 buttercups and 4 petunias : GMAT Problem Solving (PS)
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 22 Jan 2017, 17:56

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Florist 2azaleas, 3 buttercups and 4 petunias

Author Message
TAGS:

### Hide Tags

Senior Manager
Joined: 10 Nov 2010
Posts: 267
Location: India
Concentration: Strategy, Operations
GMAT 1: 520 Q42 V19
GMAT 2: 540 Q44 V21
WE: Information Technology (Computer Software)
Followers: 5

Kudos [?]: 301 [0], given: 22

Florist 2azaleas, 3 buttercups and 4 petunias [#permalink]

### Show Tags

16 Mar 2011, 05:34
1
This post was
BOOKMARKED
00:00

Difficulty:

(N/A)

Question Stats:

80% (04:02) correct 20% (00:54) wrong based on 7 sessions

### HideShow timer Statistics

10) A florist has 2 azaleas, 3 buttercups and 4 petunias .She puts two flowers together at random in a bouquet. however, the customer calls and stays that she does not want two of the same flower.What is the probability that the florist does not have to change the bouquet?

[Reveal] Spoiler: Peek
Rephrase:- probability that both the two flowers selected are different.

probability that she select one azaleas and one 1 buttercups

2/9*3/8 = 1/12

probability that she select one buttercups and one petunias
3/9*4/8= 1/6

probability that she select one petunias and one azaleas

4/9*2/8 =1/9

total probability that both the flowers ill be different -- 1/12+1/6+1/9 = 13/36

Guys whts wrong in this method

_________________

The proof of understanding is the ability to explain it.

Manager
Joined: 03 Mar 2011
Posts: 90
Location: United States
Schools: Erasmus (S)
GMAT 1: 730 Q51 V37
GPA: 3.9
Followers: 2

Kudos [?]: 137 [0], given: 12

Re: Florist 2azaleas, 3 buttercups and 4 petunias [#permalink]

### Show Tags

16 Mar 2011, 05:45
You should multiply each probability by 2, since it could be Azalea-Buttercup boquet, or Buttercup-Azalea boquet, so you have corresponding probabilities 1/6, 1/3, 2/9. Actually 2 is a number of possible combinations of 2 objects. So the answer is 1/6+1/3+2/9=(6+12+8)/36=13/18
_________________

If my post is useful for you not be ashamed to KUDO me!
Let kudo each other!

Senior Manager
Joined: 17 Mar 2011
Posts: 452
Location: United States (DC)
Concentration: General Management, Technology
GMAT 1: 760 Q49 V45
GPA: 3.37
WE: Information Technology (Consulting)
Followers: 11

Kudos [?]: 183 [1] , given: 5

Re: Florist 2azaleas, 3 buttercups and 4 petunias [#permalink]

### Show Tags

18 Mar 2011, 04:36
1
KUDOS
Another way to solve it is to consider the circumstances that she WOULD have to change the bouquet, and then subtract that probability that from one.

I found it to be easier since there are fewer combinations to account for:
A1+A2, B1+B2, B1+B3, B2+B3, P1+P2, P1+P3, P1+P4, P2+P3, P2+P4, P3+P4

10/36 is the probability that she WILL have to change the bouquet, so 26/36 or 13/18 is the probability that she will not.
Manager
Joined: 07 Dec 2010
Posts: 116
Concentration: Marketing, General Management
Followers: 0

Kudos [?]: 31 [0], given: 12

### Show Tags

11 Aug 2011, 20:49
A florist has 2 azaleas, 3 buttercups, and 4 petunias. She puts two flowers together at
random in a bouquet. However, the customer calls and says that she does not want
two of the same flower. What is the probability that the florist does not have to
change the bouquet?

5/18
13/18
1/9
1/6
2/9
Manager
Joined: 16 May 2011
Posts: 204
Concentration: Finance, Real Estate
GMAT Date: 12-27-2011
WE: Law (Law)
Followers: 1

Kudos [?]: 76 [4] , given: 37

### Show Tags

11 Aug 2011, 21:18
4
KUDOS
1
This post was
BOOKMARKED
2 azaleas, 3 buttercups, and 4 petunias for total of 9:
same flower:
2 azaleas- 2/9*1/8 of choosing the same flower.
3 buttercups- 3/9*2/8
4 petunias - 4/9*3/8
2/72+6/72+12/72=20/72 Probability to chhose the same flower.

we want the probability of not choosing so 1-20/72=52/72=26/36=13/18
VP
Status: There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Joined: 08 May 2009
Posts: 1353
Followers: 17

Kudos [?]: 240 [3] , given: 10

### Show Tags

11 Aug 2011, 22:35
3
KUDOS
required probability = 1- [ probability of both being A'z + probability of both being B'p + probability of both being P'n]

= 1- [ 2/9 * 1/8 + 3/9 * 2/8 + 4/9 * 3/8 ] = 1- 5/18 = 13/18.

Hence B.
_________________

Visit -- http://www.sustainable-sphere.com/
Promote Green Business,Sustainable Living and Green Earth !!

Intern
Joined: 22 Jun 2010
Posts: 6
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: Florist 2azaleas, 3 buttercups and 4 petunias [#permalink]

### Show Tags

03 Sep 2011, 22:39
Guys, when you use 1-p, why don't you take into account the order and multiply the result, in other words there are 2 azaleas so you should imo

2/9*1/8*2 as you can change order of choosing azalea 1 and 2

I understand that it is wrong from the answer but stlill can't get it
Manager
Joined: 04 Jun 2011
Posts: 189
Followers: 0

Kudos [?]: 52 [1] , given: 21

Re: Florist 2azaleas, 3 buttercups and 4 petunias [#permalink]

### Show Tags

06 Sep 2011, 11:28
1
KUDOS
1
This post was
BOOKMARKED
Yangstr wrote:
Guys, when you use 1-p, why don't you take into account the order and multiply the result, in other words there are 2 azaleas so you should imo

2/9*1/8*2 as you can change order of choosing azalea 1 and 2

I understand that it is wrong from the answer but stlill can't get it

ok.. dint really get your q... can you pls elucidate...

however here is my method... prob(diff flowers) = 1- prob (same flowers)

so prob of having same 2 flowers is . for 2 azaleas can be chosen in 2c2 or 1 way

similarly 2 buttercups can be chosen from 3 in 3c2 or 3 ways

and 2 pertunias from 4 in 4c2 or 6 ways...

therefore total ways is 1+3+6 or 10

total number of possible outcomes is 9c2 or 36

therefore probability of getting the same flowers is 10/36. Probability of not having same flowers is 1-10/36 or 26/36 or 13/18
Re: Florist 2azaleas, 3 buttercups and 4 petunias   [#permalink] 06 Sep 2011, 11:28
Similar topics Replies Last post
Similar
Topics:
1 4^-4/16^-3=? 3 12 Jan 2017, 17:18
25 4^3 + 4^3 + 4^3 + 4^3 = 5 02 Sep 2015, 02:16
7 For a fundraising dinner, a florist is asked to create flowe 5 11 Apr 2014, 14:40
5 What is 92% of 3/4? 7 02 Dec 2012, 13:18
10 A florist has 2 azaleas, 3 buttercups, and 4 petunias. She 9 22 Jan 2011, 08:25
Display posts from previous: Sort by