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Food Num. of calories per kilogram Num. of grams of protein

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Food Num. of calories per kilogram Num. of grams of protein [#permalink] New post 09 May 2006, 16:41
Food Num. of calories per kilogram Num. of grams of protein per kilo

S 2,000 150

T 1,500 90


36. The table above gives the number of calories and grams of protein per kilogram of food S and T. If a total of 7 kilograms of S and T are combined to make a certain food mixture, how many kilograms of food S are in the mixture?

(1) The mixture has a total of 12,000 calories.

(2) The mixture has a total of 810 grams of protein


I REALLY NEED A GOOD EXPLAINATION ON THIS ONE.
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Re: Algebra [#permalink] New post 09 May 2006, 18:06
andrecrompton wrote:
Food Num. of calories per kilogram Num. of grams of protein per kilo

S 2,000 150
T 1,500 90

36. The table above gives the number of calories and grams of protein per kilogram of food S and T. If a total of 7 kilograms of S and T are combined to make a certain food mixture, how many kilograms of food S are in the mixture?

(1) The mixture has a total of 12,000 calories.
(2) The mixture has a total of 810 grams of protein

I REALLY NEED A GOOD EXPLAINATION ON THIS ONE.

the answer should be D.

i. using trail and error, s = 3 and t = 4
= 3x2000+4x1500 = 12,000

i. using the similar approach also s = 3 and t = 4
= 3x150 + 4x 90 = 810

no any other value for s and t satisfy the above constraoints...
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 [#permalink] New post 09 May 2006, 19:51
Assuming s kg of food S are used, then T would be (7-s)kg.

St1:
2000s + 1500(7-s) = 12,000

We can solve for s to get the amt of food S used. Sufficient.

St2:
150s + 90(7-s) = 810.
Similarly, we can solve for s to get the amount of food S used. Sufficient.

Ans D
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 [#permalink] New post 10 May 2006, 10:15
Using (1)
2000x + 1500y = 12,000
x + y = 7

We can get x and y, hence sufficient.

Using (2)
Same way we can get x and y. So sufficient

Hence D
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 [#permalink] New post 11 May 2006, 00:15
Hi,
Agree with D, because:

Statement 1 is sufficient: suppose x is number of kg of S and y is number of kg of K
2000*x+1500*y=12000
x+y=7, combining both equation we can find x and y

Statement 2 is sufficient: 150*x+ 90*y=810, x+y=7. We can find x.
  [#permalink] 11 May 2006, 00:15
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