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Foodmart customers regularly buy at least one

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Foodmart customers regularly buy at least one [#permalink] New post 29 Aug 2010, 16:38
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100% (02:16) correct 0% (00:00) wrong based on 2 sessions
Foodmart customers regularly buy at least one of the following products: milk, chicken, or apples. 60% of shoppers buy milk, 50% buy chicken, and 35% buy apples. If 10% of the customers buy all 3 products, what percentage of Foodmart customers purchase exactly 2 of the products listed above?
 5%
 10%
 15%
 25%
 30%
[Reveal] Spoiler: OA
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Kudos [?]: 75 [0], given: 50

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Re: Foodmart customers regularly buy at least one [#permalink] New post 29 Aug 2010, 18:16
seekmba wrote:
Foodmart customers regularly buy at least one of the following products: milk, chicken, or apples. 60% of shoppers buy milk, 50% buy chicken, and 35% buy apples. If 10% of the customers buy all 3 products, what percentage of Foodmart customers purchase exactly 2 of the products listed above?
 5%
 10%
 15%
 25%
 30%



Total = n(A) + n(B) - n(Exactly 2 products) -2 (AnBnC) + Neither.

Neither is zero.

Hence 100 = 60 + 50 + 35 - n (Exactly 2 products) - 2*10

100 = 125 - n (Exactly 2 products) => n (Exactly 2 products) = 25.

Answer: D
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SVP
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Joined: 17 Feb 2010
Posts: 1568
Followers: 12

Kudos [?]: 123 [0], given: 6

Re: Foodmart customers regularly buy at least one [#permalink] New post 29 Aug 2010, 19:15
Thanks ezhilkumarank.

Just wanted to confirm the formula:

Total = n(A) + n(B) n(C0 - n(Exactly 2 products) -2 (AnBnC) + Neither...right???
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Kudos [?]: 75 [0], given: 50

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Re: Foodmart customers regularly buy at least one [#permalink] New post 29 Aug 2010, 19:22
seekmba wrote:
Thanks ezhilkumarank.

Just wanted to confirm the formula:

Total = n(A) + n(B) n(C0 - n(Exactly 2 products) -2 (AnBnC) + Neither...right???


Total = n(A) + n(B) n(C) - n(Exactly 2 products) -2 (AnBnC) + Neither

Correct. I swallowed a part of the formula in the hurry to complete my post. :lol:
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Re: Foodmart customers regularly buy at least one   [#permalink] 29 Aug 2010, 19:22
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