For a certain game, three numbers are drawn, each from 1 to 10. A player can win if the product of his or her three numbers is odd. Initially, the same number may be picked up to three times. Later, the rules are changed so that each number may only be picked once. Approximately how much does this reduce a person's probability of winning?

A. 0.04

B. 0.08

C. 0.1

D. 0.125

E. 0.5

I'm making some mistake while calculating the probability for the second part ,can someone explain the mistake here ?

For second part :

Total number of outcomes = 10*10*10=1000

Total number of favourable outcomes (i.e. picking 3 out 5 odd numbers ) = 5C3 = 10

Probability = 1/100 = 0.01