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VP
Joined: 14 Sep 2005
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For a certain sequence, A(1)= -1, A(2)=1. When n>=3, [#permalink]
 11 Dec 2005, 06:35
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For a certain sequence, A(1)= -1, A(2)=1. When n>=3, A(n)=A(n-1)-A(n-2), what is the sum of the first 1000 items?
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Director
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A1=-1, A2=1,A3=2, A4=1, A5=-1,A6=-2,A7=-1,A8=1,A9=2,A10=1 so seems like 300
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Manager
Joined: 20 Nov 2005
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christoph wrote: 2 !
Can you explain your answer?
I am getting 0...
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SVP
Joined: 30 Sep 2004
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stretchad wrote: christoph wrote: 2 ! Can you explain your answer? I am getting 0... sequence is -1121-1-2, which adds to 0 ! sum of 1st to 996th-item is 0. 997th item is -1, etc..so its not 2 but 3 !
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