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# For a finite sequence of nonzero numbers, the number of

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Manager
Joined: 11 Jan 2007
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For a finite sequence of nonzero numbers, the number of [#permalink]  25 Feb 2007, 09:13
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1.For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4,
-6 ?

A.One
B.Two
C.Three
D.Four
E.Five

Ans.C
_________________

cool

Manager
Joined: 09 Jan 2007
Posts: 240
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Kudos [?]: 7 [0], given: 0

Senior Manager
Joined: 24 Oct 2006
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Quote:
1.For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4,
-6 ?

The sequence: 1 -3 2 5 -4 -6
Just muliply the consecutive nos.
Check how many are -ve results. That is what is the q.

We'll see:
1*-3=-3
-3*2=-6
2*5=+ve
5*-4=-20
-4*-6=+ve

So the no of -ve reults is 3
Manager
Joined: 09 Jan 2007
Posts: 240
Followers: 1

Kudos [?]: 7 [0], given: 0

Sumithra wrote:
Quote:
1.For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4,
-6 ?

The sequence: 1 -3 2 5 -4 -6
Just muliply the consecutive nos.
Check how many are -ve results. That is what is the q.

We'll see:
1*-3=-3
-3*2=-6
2*5=+ve
5*-4=-20
-4*-6=+ve

So the no of -ve reults is 3

Thanks Sumithra
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