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Director
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For a finite sequence of nonzero numbers, the number of [#permalink]
 17 May 2007, 07:05
For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the
sequence 1, -3,2,5,-4,-6 ?
One
Two
Three
Four
Five
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Re: Number Property Question - Please help [#permalink]
17 May 2007, 08:15
alimad wrote: For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the
sequence 1, -3,2,5,-4,-6 ?
One
Two
Three
Four
Five
Three variations
(1,-3), (-3,2) and (5,-4)
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Re: Number Property Question - Please help [#permalink]
17 May 2007, 08:45
kirakira wrote: alimad wrote: For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the
sequence 1, -3,2,5,-4,-6 ?
One
Two
Three
Four
Five Three variations (1,-3), (-3,2) and (5,-4) can you explain how you did it?
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Manager
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the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative
1,-3,2,5,-4,-6
(1,-3), (-3,2) and (5,-4)
will give the product as -iv.
so no. of variations is 3.
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Director
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"number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative "
I don't see two consecutive terms, care to explain further please. Thanks
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