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For a finite sequence of nonzero numbers, the number of

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Director
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For a finite sequence of nonzero numbers, the number of [#permalink] New post 17 May 2007, 06:05
For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the
sequence 1, -3,2,5,-4,-6 ?

One
Two
Three
Four
Five
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Manager
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Re: Number Property Question - Please help [#permalink] New post 17 May 2007, 07:15
alimad wrote:
For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the
sequence 1, -3,2,5,-4,-6 ?

One
Two
Three
Four
Five


Three variations

(1,-3), (-3,2) and (5,-4)
Senior Manager
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Re: Number Property Question - Please help [#permalink] New post 17 May 2007, 07:45
kirakira wrote:
alimad wrote:
For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the
sequence 1, -3,2,5,-4,-6 ?

One
Two
Three
Four
Five


Three variations

(1,-3), (-3,2) and (5,-4)


can you explain how you did it?
Manager
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 [#permalink] New post 17 May 2007, 11:26
the number of variations in sign is defined as the number of pairs of consecutive terms of
the sequence for which the product of the two consecutive terms is negative

1,-3,2,5,-4,-6

(1,-3), (-3,2) and (5,-4)

will give the product as -iv.

so no. of variations is 3.
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 [#permalink] New post 18 May 2007, 04:47
"number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative "

I don't see two consecutive terms, care to explain further please. Thanks
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  [#permalink] 18 May 2007, 04:47
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