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For a finite sequence of zero numbers, the number of [#permalink]
 04 Jul 2006, 03:22
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For a finite sequence of zero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consequtive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6.
None
1.
2.
3.
4.
OA will follow.
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SVP
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3
Pair of consecutive terms for which product si negative
(1,-3) (-3,2) (5,-4)
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Re: PS: Finite sequence. [#permalink]
04 Jul 2006, 08:20
if the order of sequence is : 1, -3, 2, 5, -4, -6, its 3.
if the order of sequence is : -6, -4, -3, 1, 2, 5, its 1.
BTY, what is "For a finite sequence of zero numbers"? 
M8 wrote: For a finite sequence of zero numbers, the number of variations in sign is defined ..................
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Re: PS: Finite sequence. [#permalink]
04 Jul 2006, 09:30
MA wrote: if the order of sequence is : 1, -3, 2, 5, -4, -6, its 3. if the order of sequence is : -6, -4, -3, 1, 2, 5, its 1. BTY, what is "For a finite sequence of zero numbers"? M8 wrote: For a finite sequence of zero numbers, the number of variations in sign is defined .................. I think it should be "For a finite sequence of non-zero numbers.."
Answer is 3, though I interpreted in a different way and got incorrect answer 
_________________
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Intern
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3.
1*-3 = negative
-3*2 = negative
5*-4 = negative
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Director
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Re: PS: Finite sequence. [#permalink]
04 Jul 2006, 23:39
MA wrote: if the order of sequence is : 1, -3, 2, 5, -4, -6, its 3. if the order of sequence is : -6, -4, -3, 1, 2, 5, its 1. BTY, what is "For a finite sequence of zero numbers"? Sorry guys it's my fault, of course it must be 'NONZERO numbers'.
Yes OA is 3. But I have the same question as MA has.
1, -3, 2, 5, -4, -6, its 3.
-6, -4, -3, 1, 2, 5, its 1.
According to Pearson Vue a sequence is any group of digits, but I think that sequense must always be in descending or ascending order.
Any thoughts?
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Re: PS: Finite sequence.
[#permalink]
04 Jul 2006, 23:39
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