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For a light that has an intensity of 60 candles at its sourc

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Senior Manager
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For a light that has an intensity of 60 candles at its sourc [#permalink] New post 20 Jan 2006, 15:25
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For a light that has an intensity of 60 candles at its source, the intensity in candles, S, of the light at a point d d feet from the source is given by the formula S=60k/d^2 60, where k is a constant. If the intensity of the light is 30 candles at a distance of 2 feet from the source, what is the intensity of the light at a distance of 20 feet from the source?

A. 3/10 candles
B. 1/2 candles
C. 1 1/3 candles
D. 2 candles
E. 3 candles
[Reveal] Spoiler: OA

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 [#permalink] New post 20 Jan 2006, 16:43
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ANS = 3/10

S= 60k/d^2

At 2 feet
30 = 60k/4 so k = 2

At 20 feet
S = 60 *2/20^2 = 3/10
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Re: [#permalink] New post 27 Jan 2013, 06:53
ps_dahiya wrote:
At 2 feet
30 = 60k/4 so k = 2


Why 30 equals to that? I can't seem to get it.. can you explain in more detail, pls?
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Re: Re: [#permalink] New post 27 Jan 2013, 11:49
sianissimo wrote:
ps_dahiya wrote:
At 2 feet
30 = 60k/4 so k = 2


Why 30 equals to that? I can't seem to get it.. can you explain in more detail, pls?





S=60K/d^2

Now... 30 when distance 2... 30 = 60k/4 or 60K = 30 *4
Now...Distance 20 then....S = 60k/20^2 = 30*4/(20*20) = 3/10
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Re: Re:   [#permalink] 27 Jan 2013, 11:49
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