Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: what is the value of x* [#permalink]
20 Nov 2009, 16:08

3

This post received KUDOS

Expert's post

srini123 wrote:

quick question, when (x-1)(x-2) = (x - 2) why cant we cross out (x-2) and arrive at x-1=1 and x=2 ?

Never reduce equation by variable (or expression with variable), if you are not certain that variable (or expression with variable) doesn't equal to zero. We can not divide by zero.

Never multiply (or reduce) inequality by variable (or expression with variable) if you don't know the sign of it or are not certain that variable (or expression with variable) doesn't equal to zero.

You cannot reduce by x-2 as x may be equal to 2, and in this case you are dividing by 0. _________________

Re: what is the value of x* [#permalink]
20 Nov 2009, 16:17

1

This post received KUDOS

srini123 wrote:

quick question, when (x-1)(x-2) = (x - 2) why cant we cross out (x-2) and arrive at x-1=1 and x=2 ?

As a general rule, never cross multiply variables on two sides of an equation unless we can be sure that it cannot be equal to 0.

In this case it turned out that the answer would have come the same. However, there is no way of knowing that in advance. Take the following case : (x-2)(x-2) = (x-2) ----> if we cross out (x-2) on both sides, we will get x = 3. However, x = 2 also satisfies this equation. (x-3)(x-2) = (x-2) ----> again if we cross out (x-2) on both sides we will get x = 4. However, x = 2 also satisfies this equation.

One more thing to note is that an algebraic expression, the highest power of x will determine the number of roots of x. Therefore a quadratic equation in x will always have 2 values that satisfy it. It can be that the two values are the same as they are in our case. However, they will still be treated as two values. Thus we will say that the roots of the equation are 2 and 2. _________________

Re: what is the value of x* [#permalink]
20 Nov 2009, 16:31

Expert's post

sriharimurthy wrote:

One more thing to note is that an algebraic expression, the highest power of x will determine the number of roots of x. Therefore a quadratic equation in x will always have 2 values that satisfy it. It can be that the two values are the same as they are in our case. However, they will still be treated as two values. Thus we will say that the roots of the equation are 2 and 2.

One little thing: in quadratic equation highest power of x will determine maximum # of roots. Quadratic equation can have 0, 1, or 2 roots.

When discriminant more than 0 you'll have 2 roots; When discriminant is zero you'll have 1 root (and not two treated as one); When discriminant is less than 0 you won't have any real roots.

x^2-4x+3=0 has 2 roots; x^2-4x+4=0 has 1 root; x^2-4x+5=0 has 0 real roots. _________________

Re: what is the value of x* [#permalink]
20 Nov 2009, 17:36

Bunuel wrote:

One little thing: in quadratic equation highest power of x will determine maximum # of roots. Quadratic equation can have 0, 1, or 2 roots.

When discriminant more than 0 you'll have 2 roots; When discriminant is zero you'll have 1 root (and not two treated as one); When discriminant is less than 0 you won't have any real roots.

x^2-4x+3=0 has 2 roots; x^2-4x+4=0 has 1 root; x^2-4x+5=0 has 0 real roots.

In cases when the discriminant is more than 0 or less than 0, you will always have two distinct roots. In one case real and in the other a pair of complex conjugates.

What you have stated is perfectly valid provided we specify that we are only concerned with the real and distinct roots of an equation.

When the discriminant is 0, you are right in saying that it will have only one distinct root. However, the term root by itself does not imply distinct or real. Thus when the discriminant is 0 it actually has a double root (which is to account for its multiplicity).

So, unless we are asked to find the number of distinct real solutions of a quadratic equation am I not right in saying that it will always have two roots? _________________

Re: what is the value of x* [#permalink]
20 Nov 2009, 18:20

Expert's post

sriharimurthy wrote:

In cases when the discriminant is more than 0 or less than 0, you will always have two distinct roots. In one case real and in the other a pair of complex conjugates.

What you have stated is perfectly valid provided we specify that we are only concerned with the real and distinct roots of an equation.

When the discriminant is 0, you are right in saying that it will have only one distinct root. However, the term root by itself does not imply distinct or real. Thus when the discriminant is 0 it actually has a double root (which is to account for its multiplicity).

So, unless we are asked to find the number of distinct real solutions of a quadratic equation am I not right in saying that it will always have two roots?

When the discriminant is negative quadratic equation has no real roots. As I stated above.

GMAT is dealing ONLY with real numbers. No need to complicate this.

When the quadratic equation has one root it's rarely called "double root". More common to say that it has 1 root. So usually when we say root of equation we think about the distinct root, even if we don't specify it.

So we can say: Discriminant positive - 2 roots; Discriminant 0 - 1 root, even not specifying that it's distinct; Discriminant negative - no real roots, for GMAT no root at all.

Though you are right in saying that quadratic equation always has two roots if: A. We consider complex roots, which is not the case for GMAT; B. We consider the concept of "double root", though I've never seen GMAT even mentioning the double root.

From my experience in GMAT, we can say that it's considering quadratic equation as parabola and the roots as its intersection with X-axis. One tangent point - one root, two intersections - 2 roots, no intersection - no root.

Again as I said no need to complicate. _________________

Re: For all integers n, n* = n(n – 1). What is the value of x* w [#permalink]
31 Jul 2014, 05:58

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

It has been a fairly long time since I have posted here, but I definitely did not want to sign off without giving readers a quick update on my personal...