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Let's take 6n=2 or in other words, n=1/3
The difference between 7^2 and 6^2 = 49-36 = 13
Therefore, as we increase n, the difference between the 2 terms will increase by a base of 13 exponent any number. Thus, the answer is that the solution is divisible by 13
Why would you want to factor 13? Or am I just missing the point here?
I also did not follow ..
If n=1, 7^6n-6^6n=1^6=1 so d)
Also, in the question stem, should n be associated with 6 or with 7?
Let's take 6n=2 or in other words, n=1/3 The difference between 7^2 and 6^2 = 49-36 = 13 Therefore, as we increase n, the difference between the 2 terms will increase by a base of 13 exponent any number
What if n = 1/6??? the difference comes up to 1 which is not divisible by 13.
I'm sorry, but x^z - y^z is NOT equal to (x-y)^z. _________________
AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993
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