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Re: GMAT Prep 1: Symbolism [#permalink]
13 Feb 2010, 10:25

carriedinterest wrote:

For all positive integers m, M=3m when m is odd and M=1/2 when m is even. Which of the following is equivalent to 9 x 6?

A) 81 B) 54 C) 36 D) 27 E) 18

Clear, concise explanations welcome!

It should be D.... Please check...

9 x 6 = (3x9) x (6 x 1/2) = 27 x 3 = 27 _________________

Cheers! JT........... If u like my post..... payback in Kudos!!

|Do not post questions with OA|Please underline your SC questions while posting|Try posting the explanation along with your answer choice| |For CR refer Powerscore CR Bible|For SC refer Manhattan SC Guide|

Re: GMAT Prep 1: Symbolism [#permalink]
13 Feb 2010, 10:26

carriedinterest wrote:

LJ wrote:

You posted this question incorrectly because all of the answers need to be surrounded with a box, or in your notation, an underline. Failing to do this misses the point of the problem.

Good spot. I've corrected the answer choices. You're obviously familiar with the problem - care to answer?

9 = 27 and 6 = 3, multiplied together they = 81.

Because the answer choices are notated with the _, however, you need to calculate the "_" value of 81

question itself: For all positive integers m, {m}=3m, when m is odd, and {m}=m/2 when m is even. which of the following is equivalent to {9}*{6} ? a){81} b){54} c){36} d){27} e){18}

my solution: solution seemed to me very easy 9 is odd and 6 is even so ={9*3}*{6/2}=27*3=81

Re: GMAT Prep1: positive integer m [#permalink]
17 May 2010, 20:42

i made the same mistake with the boxes .....gmat is really smart with tricking you with such questions .....one thing that i noticed was that i make a lot of mistakes when converting the algebraic expression so lets say they asked about the product ...i will for some reason start adding in my calculation

Need help with these 5 GMAT Prep questions... [#permalink]
08 Dec 2010, 13:51

Guys, as my G-day is approaching, I am putting more and more effort in improving my Quant. However, I seem to have troubles with some basic concepts. Below are the 5 questions which I know have simple explanations but are for some reason difficult for me to understand. If you can explain the solutions for any of them, I would greatly appreciate it! Cheers!

Re: Tough Algebra, Can anyone help me? Thanks!! [#permalink]
26 Feb 2011, 23:18

IanStewart wrote:

We know that [9] = 3*9 = 27, since [x] = 3x when x is odd. We also know that [6] = 3, since [x] = x/2 when x is even. So [9]*[6] = 27*3 = 81.

Now, many people choose the wrong answer to this question, despite doing all of the work correctly, because they do not notice that the answer choices are all in boxes - a devious GMAT trap. So the answer choice which reads [81] is not equal to the number 81; it is equal to 3*81 = 243, because [x] = 3x when x is odd. The correct answer here is [27], which is equal to the number 81.

Thanks mate! This one was my big "AHA! Gotcha" GMAT moment for the day. A clever trap! _________________

-DK --------------------------------------------------------- If you like what you read then give a Kudos! Diagnostic Test: 620 The past is a guidepost, not a hitching post. ---------------------------------------------------------

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