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For all positive integers m and v, the expression m Θ v

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Director
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For all positive integers m and v, the expression m Θ v [#permalink] New post 30 Apr 2006, 06:48
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A
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For all positive integers m and v, the expression m Θ v represents the remainder when m is divided by v. What is the value of {(98Θ33)Θ17)-(98Θ(33Θ17)}?

A. -10
B. -2
C. 8
D. 13
E. 17
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Re: PS: m@v [#permalink] New post 30 Apr 2006, 07:45
(98Θ33)Θ17) - (98Θ(33Θ17)

(32Θ17) - (98Θ16)

15 - 2 = 13.

So D.
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Re: PS: m@v [#permalink] New post 01 May 2006, 01:42
ccax wrote:
(98Θ33)Θ17) - (98Θ(33Θ17)

(32Θ17) - (98Θ16)

15 - 2 = 13.

So D.


Ccax please elaborate your answer. Thank you.
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 [#permalink] New post 01 May 2006, 02:13
98Θ33 = 32

32Θ17= 15

33Θ17= 16

98Θ16 = 2

15 - 2 = 13
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 [#permalink] New post 02 May 2006, 17:42
(98Θ33)Θ17 = 32Θ17 = 15
98Θ(33Θ17) = 98Θ16 = 2

15-2 = 13
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 [#permalink] New post 02 May 2006, 22:49
Agreed its D - 13



Good practice: I get these simple computation intensive problems wrong! Keep em' comin'!
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 [#permalink] New post 03 May 2006, 05:44
Agree with D :wink:
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Re: PS: m@v [#permalink] New post 03 May 2006, 19:21
Professor wrote:
ccax wrote:
(98Θ33)Θ17) - (98Θ(33Θ17)
(32Θ17) - (98Θ16)
15 - 2 = 13.
So D.


this is pretty clear.


:oops: Now I got it. Another quick glance at the question and the problem does not exist anymore.
I must be more careful. :(
Very easy question. :wink:
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 [#permalink] New post 05 May 2006, 04:07
Yes, tt is D
98@33 reminder is 32, 32@17 reminder is 15
33@17 reminder is 16, 98@16 reminder is 2
15-2=13
  [#permalink] 05 May 2006, 04:07
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For all positive integers m and v, the expression m Θ v

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