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For any numbers a and b, a ┬╖ b = a + b -ab If a [#permalink]
25 Jan 2004, 18:08

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

For any numbers a and b, a ┬╖ b = a + b -ab

If a ┬╖ b = 0, which of the following CANNOT be a value of b?

a 2
b 1
c 0
d -1
e -(3/2)

I post this to see if anyone has the same issues with this problem that I have.

I did the final unseen practice test tonight, and this problem torpedoed the whole damn thing. And if I have a problem with this deficiency on the test, I'll go seriously nuts. But maybe I'm overreacting. You tell me.

DS does give scope to creep in misleading stuff . For ex, the other day I saw a problem which asked for 999 th term of a sequence S with the following conditions

a) The first four terms of sequence S are (1+1)^2, (2+1)^2, (3+1)^2, (4+1)^2
b) The nth term of the sequence is given by (n+1)^2

The reason that I claimed that this problem was misleading is that, ever since I took Algebra in 8th grade, I understood that the dot " ┬╖ " means multiply.

Are Mr. Young and the rest of the Lexington public school faculty the only people that teach that dot means multiply?

There are dozens of symbols that ETS could have used that don't have a specific, widely held connotation.