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# For any numbers a and b, a#b=a + b - ab. If a#b=0, which of

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For any numbers a and b, a#b=a + b - ab. If a#b=0, which of [#permalink]

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05 Jul 2012, 01:33
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For any numbers a and b, a#b=a + b - ab. If a#b=0, which of the following CANNOT be a value of b?

A. 2
B. 1
C. 0
D. -1
E. -3/2
[Reveal] Spoiler: OA

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Last edited by Bunuel on 11 Apr 2013, 04:05, edited 2 times in total.
Edited the question.
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Re: For any numbers a and b, ab= a + b - ab. If ab=0, which of [#permalink]

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05 Jul 2012, 01:51
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Stiv wrote:
For any numbers a and b, ab= a + b - ab. If ab=0, which of the following CANNOT be a value of b?

A. 2
B. 1
C. 0
D. -1
E. -3/2

Some function (#) is defined for all numbers $$a$$ and $$b$$ as $$a#b= a + b - ab$$.

Now, since given that $$a#b=0$$, then $$a + b - ab=0$$ --> $$a=\frac{b}{b-1}$$ --> if $$b=1$$ then the given expression is undefined so $$b$$ cannot equal to 1.

Or: $$a + b - ab=0$$ --> $$(a-1)(1-b)+1=0$$ --> $$(a-1)(1-b)=-1$$. If $$b=1$$, then $$(a-1)(1-b)=0$$ not -1, so $$b$$ cannot equal to 1.

Hope it's clear.
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Re: For any numbers a and b, ab= a + b - ab. If ab=0, which of [#permalink]

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05 Jul 2012, 23:55
Can someone pls edit the question.? i was wondering where i was going wrong thinking. question was ab=a+b-ab => 2ab=a+b. and then saw bunuel's reply then understood what the question was!
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Re: For any numbers a and b, ab= a + b - ab. If ab=0, which of [#permalink]

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25 Jul 2012, 00:40
asax wrote:
Can someone pls edit the question.? i was wondering where i was going wrong thinking. question was ab=a+b-ab => 2ab=a+b. and then saw bunuel's reply then understood what the question was!

Even I got it wrong...
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Re: For any numbers a and b, ab= a + b - ab. If ab=0, which of [#permalink]

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11 Apr 2013, 03:59
asax wrote:
Can someone pls edit the question.? i was wondering where i was going wrong thinking. question was ab=a+b-ab => 2ab=a+b. and then saw bunuel's reply then understood what the question was!

Yes indeed, very annoying..
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Re: For any numbers a and b, ab= a + b - ab. If ab=0, which of [#permalink]

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11 Apr 2013, 04:06
notsureifseriousor wrote:
asax wrote:
Can someone pls edit the question.? i was wondering where i was going wrong thinking. question was ab=a+b-ab => 2ab=a+b. and then saw bunuel's reply then understood what the question was!

Yes indeed, very annoying..

Done: edited the question.
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Re: For any numbers a and b, a#b=a + b - ab. If a#b=0, which of [#permalink]

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11 Apr 2013, 04:15
Stiv wrote:
For any numbers a and b, a#b=a + b - ab. If a#b=0, which of the following CANNOT be a value of b?

A. 2
B. 1
C. 0
D. -1
E. -3/2

------------------------------------------
for me the fastest way must be the use of answer choices to find the value of a if a will be an integer after putting the value of of b as given in the answer choices then the answer will be correct with no cumbersome calculations & its fast too ....!!
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Re: For any numbers a and b, a#b=a + b - ab. If a#b=0, which of [#permalink]

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16 Jul 2014, 20:40
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Re: For any numbers a and b, a#b=a + b - ab. If a#b=0, which of [#permalink]

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17 Jul 2014, 06:27
Can I do it this way?

I will just plug the number in to see if we can solve for a.

a#b=a+b-ab and a#b=0

=> a+b-ab=0

A. b=2 -> a=2
B. b=1 -> a+1-a=0 -> 1=0???
C. b=0 -> a=0
D. b=-1 -> a=1/2
E. b=-3/2 -> a= 3/5

So it's clear that b cannot be 1!
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Re: For any numbers a and b, a#b=a + b - ab. If a#b=0, which of [#permalink]

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17 Jul 2014, 06:37
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linhnd1492 wrote:
Can I do it this way?

I will just plug the number in to see if we can solve for a.

a#b=a+b-ab and a#b=0

=> a+b-ab=0

A. b=2 -> a=2
B. b=1 -> a+1-a=0 -> 1=0???
C. b=0 -> a=0
D. b=-1 -> a=1/2
E. b=-3/2 -> a= 3/5

So it's clear that b cannot be 1!

Yes, it's a valid approach.

Check other function questions in our Special Questions Directory:

Operations/functions defining algebraic/arithmetic expressions
Symbols Representing Arithmetic Operation
Rounding Functions
Various Functions

Hope it helps.
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Re: For any numbers a and b, a#b=a + b - ab. If a#b=0, which of [#permalink]

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01 Jan 2016, 18:24
Use answer choices to see whether a valid value for a can be determined.
B shows that 1=0 which is never true, so that is the answer.
Re: For any numbers a and b, a#b=a + b - ab. If a#b=0, which of   [#permalink] 01 Jan 2016, 18:24
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