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For any triangle in the xy-coordinate plane, the center of T

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For any triangle in the xy-coordinate plane, the center of T [#permalink] New post 12 Jun 2008, 11:23
For any triangle in the xy-coordinate plane, the center of T is defined to be the point whose x-coordinate in the average(mean) of the x-coordinate of the vertices of T and whose y-coordinate in the average of the y-coordinate of the vertices of T. If a certain triangle has vertices at the points(0,0) and (6,0) and center at point(3,2) what are the coordinates of the remaining vertex?
3, 4
3, 6
4, 9
6, 4
9, 6

please explain the answer. Thanks
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Re: Triangle-Gmat prep [#permalink] New post 12 Jun 2008, 11:42
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B(3,6)

Mean of (0,0) , (6,0) & (x,y) is (3,2)

(0+6+x)/3=3 => x=3
(0+0+y)/3=2 => y=6
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Re: Triangle-Gmat prep [#permalink] New post 13 Jun 2008, 03:21
Capthan wrote:
For any triangle in the xy-coordinate plane, the center of T is defined to be the point whose x-coordinate in the average(mean) of the x-coordinate of the vertices of T and whose y-coordinate in the average of the y-coordinate of the vertices of T. If a certain triangle has vertices at the points(0,0) and (6,0) and center at point(3,2) what are the coordinates of the remaining vertex?
3, 4
3, 6
4, 9
6, 4
9, 6

please explain the answer. Thanks


mean of (0,0) and (6,0) and (x,y) is (3,2)
therefore
0+6+x/3 = 3 therefore x = 3
and
0+0+y/3 = 2 therefore y = 6

therefore point is (3,6)
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Re: Triangle-Gmat prep   [#permalink] 13 Jun 2008, 03:21
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For any triangle in the xy-coordinate plane, the center of T

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