For any triangle in the xy-coordinate plane, the center of T is defined to be the point whose x-coordinate in the average(mean) of the x-coordinate of the vertices of T and whose y-coordinate in the average of the y-coordinate of the vertices of T. If a certain triangle has vertices at the points(0,0) and (6,0) and center at point(3,2) what are the coordinates of the remaining vertex?
please explain the answer. Thanks
mean of (0,0) and (6,0) and (x,y) is (3,2)
0+6+x/3 = 3 therefore x = 3
0+0+y/3 = 2 therefore y = 6
therefore point is (3,6)
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