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For each month of next year, Company R's monthly revenue

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For each month of next year, Company R's monthly revenue [#permalink] New post 07 Dec 2007, 08:38
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Question Stats:

59% (01:48) correct 41% (01:25) wrong based on 67 sessions
For each month of next year, Company R's monthly revenue target is x dollars greater than its monthly revenue target for the preceding month. What is Company R's revenue target for March of next year?

(1) Company R's revenue target for December of next year is $310,000

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of next year.
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Re: For each month of next year, Company R's monthly revenue [#permalink] New post 07 Dec 2007, 09:05
Answer is C

1. We know the target for December is $310,000. We know March is 9 months earlier, but we don't know x.

2. We know X is $10,000 but have no starting point to find March with.

combined we know $310,000 is December
Nov: $300,000
Oct: $290,000
Sep: $280,000
Aug: $270,000
July: $260,000
June: $250,000
May: $240,000
April: $230,000
March: $220,000

or you could just take $310,000 - ($10,000 * 9 months) = $220,000
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Re: For each month of next year, Company R's monthly revenue [#permalink] New post 07 Dec 2007, 09:11
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J=target revenue for January

Stmt 1. J+11x=310,000

Two variables, insuff

Stmt 2. J+9x=J+5x +30,000

Two variables, insuff

Together we have two equations with two variables. Suff

Ans C.
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Re: For each month of next year, Company R's monthly revenue [#permalink] New post 29 Aug 2011, 13:08
eschn3am wrote:
Answer is C

1. We know the target for December is $310,000. We know March is 9 months earlier, but we don't know x.

2. We know X is $10,000 but have no starting point to find March with.

combined we know $310,000 is December
Nov: $300,000
Oct: $290,000
Sep: $280,000
Aug: $270,000
July: $260,000
June: $250,000
May: $240,000
April: $230,000
March: $220,000

or you could just take $310,000 - ($10,000 * 9 months) = $220,000


Please help me understand how did we calculate x=10,000 from statement 2.
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Re: For each month of next year, Company R's monthly revenue [#permalink] New post 29 Aug 2011, 13:28
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DeeptiM wrote:
eschn3am wrote:
Answer is C

1. We know the target for December is $310,000. We know March is 9 months earlier, but we don't know x.

2. We know X is $10,000 but have no starting point to find March with.

combined we know $310,000 is December
Nov: $300,000
Oct: $290,000
Sep: $280,000
Aug: $270,000
July: $260,000
June: $250,000
May: $240,000
April: $230,000
March: $220,000

or you could just take $310,000 - ($10,000 * 9 months) = $220,000


Please help me understand how did we calculate x=10,000 from statement 2.


It is an arithmetic progression:

Let R be the revenue target for June.
For July; revenue target=R+x
For August; revenue target=R+2x
For September; revenue target=R+3x

(2) Company R's revenue target for September of next year is $30,000 greater than its revenue target for June of mext year.

\(R+3x-R=30000\)
\(x=10000\)-------------------------1
Not Sufficient.

(1) Company R's revenue target for December of next year is $310,000

Let Jan's revenue target be J,

Common difference is "x". First term(January)=J; Last term or 12th term, say D(December)

\(A_n=A_1+(n-1)d\)

\(D=J+(n-1)x\)
\(D=J+(12-1)x\)

\(310000=J+11x\)-----2
Not Sufficient.

Using 1 and 2, we get J and we know x.

March Revenue Target= J+2x
Sufficient.

Ans: "C"
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Re: For each month of next year, Company R's monthly revenue [#permalink] New post 29 Aug 2011, 15:52
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JAN FEB MAR APR MAY......... .DEC
a a+x a+2x a+11x


a+2x=?

1. Not Sufficient
a+11x = 310000

we dont know a or x. In other words different a , will give different x.

2. Not sufficient

a+8x = 30000 + a+5x

x can be found . But no info on a.

Together,

a+11x = 310000 and we have x from 2.

Hence this is Sufficient.

Answer is C.
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Re: For each month of next year, Company R's monthly revenue [#permalink] New post 28 Nov 2014, 08:14
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Re: For each month of next year, Company R's monthly revenue   [#permalink] 28 Nov 2014, 08:14
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