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For every positive even integer n , the function h(n) is [#permalink]
21 Mar 2008, 02:36
This topic is locked. If you want to discuss this question please re-post it in the respective forum.
For every positive even integer n, the function h(n) is defined to be product of all even integers from 2 ton, inclusive. If p is the smallest prime factor of h(100) + 1, then p is
1. between 2 and 10 2. between 10 and 20 3. between 20 and 30 4. between 30 and 40 5. greater then 40
50! + 1 some number whose smallest factor has to be greater thnn 50
Thanks much! Out of curiosity - is this mentioned as a trick somewhere or did you try with different numbers to solve this problem? I just want to make sure I cover any reading material if I need to.
Re: Function, evens [#permalink]
24 Mar 2008, 06:50
az780 wrote:
notahug, what about 5*7 +1 = 35 + 1 = 36, 36 = 9*4 = (2^2)*(3^2), 2<5<7
I got what Notahug means for 5*7 +1=35+1=36 I think he did not mean that for 36, factors must be more than 5 or 7. Rather, it must not be equal to 5 or 7.
back to the question, since factors of h(n) are all ranging from 2 to 50, then it means that factors of h(n)+1 cannot be 2,3,4,5,....50. That's why he answered E
if i made a mistake, please correct me
gmatclubot
Re: Function, evens
[#permalink]
24 Mar 2008, 06:50