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# For integers a and b, (a^3-a^2-b)^1/2=7, a=? 1). a^2-a=12

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Senior Manager
Joined: 08 Aug 2005
Posts: 251
Followers: 1

Kudos [?]: 17 [0], given: 0

For integers a and b, (a^3-a^2-b)^1/2=7, a=? 1). a^2-a=12 [#permalink]  23 Nov 2005, 22:44
00:00

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(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
For integers a and b, (a^3-a^2-b)^1/2=7, a=?
1). a^2-a=12
2). b^2-b=2

OA is B
SVP
Joined: 24 Sep 2005
Posts: 1895
Followers: 11

Kudos [?]: 133 [0], given: 0

[#permalink]  23 Nov 2005, 23:52
[#permalink] 23 Nov 2005, 23:52
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# For integers a and b, (a^3-a^2-b)^1/2=7, a=? 1). a^2-a=12

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