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For integers a and b, if a 2b is not equal to 0, is

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For integers a and b, if a 2b is not equal to 0, is [#permalink] New post 09 Nov 2004, 11:26
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For integers a and b, if a – 2b is not equal to 0, is a^2-4b^2/2a-4b an integer?
(1) a is odd.
(2) a is even.

Pls explain. Ta very much! :lol:

Last edited by ninomoi on 09 Nov 2004, 15:32, edited 1 time in total.
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 [#permalink] New post 09 Nov 2004, 12:53
question has a typo...pls retype.
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 [#permalink] New post 09 Nov 2004, 15:30
Thanks! I have corrected it. :shock:
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 [#permalink] New post 09 Nov 2004, 15:39
I think the answer is D

[a^2-4b^2]/[2a-4b] = (a+2b)/2

Statement 1: a is odd
2b is always even, but if a is odd, a+2b will be odd
=> (a+2b)/2 is not an integer. Sufficient

Statement 2: a is even
a+2b will be even and therefore divisible by two.
=> (a+2b)/2 is an integer. Sufficient
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 [#permalink] New post 09 Nov 2004, 18:40
Nice explanation gayathri... Thanks
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 [#permalink] New post 10 Nov 2004, 21:55
Thanks mate! Nice explanation! D is the OA :lol:
  [#permalink] 10 Nov 2004, 21:55
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