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for integers a & b , if sqt (a^3-a^2-b) = 7 ...wat is the value of a ???

1. a^2 - a = 12 2. b^2 - b = 2

sorry guys but I don't know the OA ...I am curious to know the solution for this....

From stmt1 we get a^2-a-12=0 solving for a we get 4,-3. We can substitute in the original qun to see which of this is value of A. but we do not know the value of b. Hence insuff.

From stmt2: we get b=2 or b=-1. We still do not know the value of A. so insuff.

Combinging if a = 4 and b = -1 then the original equn is 7. so my answer is C.

guys, i have a question about these type of questions.

When they ask for 'value', do they mean a numerical value, or are they just looking to get the variable a in terms of the variable b ? Because if its just a in terms of b, then I would answer A.

You can take statement 1 , and break the stem question like such:

Actually from II we get b=-1 or 2. When we combine them we know that b has to be odd for 12a-b=49. You finally confirm that a=4 and b=-1 is the only solution that satisfies all conditions. _________________

Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.

Actually from II we get b=-1 or 2. When we combine them we know that b has to be odd for 12a-b=49. You finally confirm that a=4 and b=-1 is the only solution that satisfies all conditions.

I got C and that was my rationale. i think i'm starting to understand this concept. thanks all!!!

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