Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: For nonnegative integers x and y, what is the remainder when [#permalink]
15 Dec 2012, 14:53

good one... do you know the explanation? given x,y \geq 0; what is R in x = Qy + R 1) x=13y + 0.8y in this case we need value of 0.8y but we don't know values of x,y; Not Sufficient 2) x+y < \(10^4\); Not Sufficient

1+2 from 1) x=13.8y so from 2) 14.8y < \(10^4\) so y < \frac{\(10^4\)}{14.8} there exists multiple integer values of y less than 10^4/14.8 for which x is integer... So my answer is E.... Since OA is different, i think my thinking in the last part is wrong.... Not sure how to proceed from here....

Last edited by Amateur on 15 Dec 2012, 17:12, edited 1 time in total.

Re: For nonnegative integers x and y, what is the remainder when [#permalink]
16 Dec 2012, 05:57

shanmugamgsn wrote:

BangOn wrote:

Amateur wrote:

Bunuel.... I need your presence here..... I am becoming reckless to get a solution for this.....

Let me try

X/Y = 13+ .8 X/Y = 13 + 4/5

X and Y are integers... Possibilities of Remainder/Divisor = 4/5, 8/10, 12/15 if 4/5 X = 69 Y = 5 If 8/10 X=138 Y =10 If 12/15 X= 207 Y =15

B says we should have the total digits of X and Y less than 5 only 4/5 suffice. Hence OA.

B says we should have the total digits of X and Y less than 5 only 4/5 suffice.

Didnt this mean total no of digits less than 5? Can u explain ur soln Bangon

Yeah Sure. Total Digits in both X and Y should be less than 5. if 4/5 X = 69 Y = 5 No. Of digits in X and Y is 3 If 8/10 X=138 Y =10 No. Of digits in X and Y is 5 If 12/15 X= 207 Y =15 No. Of digits in X and Y is 5

So from C, we have only one possible solution X = 69 Y = 5 _________________

Re: For nonnegative integers x and y, what is the remainder when [#permalink]
16 Dec 2012, 13:42

JJ2014 wrote:

For nonnegative integers x and y, what is the remainder when x is divided by y?

(1) x/y = 13.8 (2) The numbers x and y have a combined total of less than 5 digits

BangOn wrote:

Amateur wrote:

Bunuel.... I need your presence here..... I am becoming reckless to get a solution for this.....

B says we should have the total digitsof X and Y less than 5 only 4/5 suffice. Hence OA.

BangOn wrote:

thank you for the explanation, statement B makes sense now. one thing- how did you get the possibilities of remainder/divisor?[/quote]

Possibilities by just multiplying the fraction .8 = 4/5 1) 4/5*1/1 = 4/5 2) 4/5 * 2/2 = 8/10 . . similarly[/quote] estimating reminders is fine.... but calculating x and y values when you have remainders, I think it is time consuming process for a 600-700 problem..... Also, B didnot say we should have total digits less than 5, b said x and y have a combined total of less than 5 digits.... if it did say the number of digits of x and y have a combined total of less than 5 you must have been correct.... but since it said less than 5 digits.... the equation will be x+y<10^4

Re: For nonnegative integers x and y, what is the remainder when [#permalink]
16 Dec 2012, 19:12

Statement -1 : X= 13 Y + .8 Y As X & Y are Non negative integers ,hence .8Y integer Possible values of Y for which R =.8 Y is an integers : 5,10,15,... As there are multiple values of Y for which R is an integers- Not sufficient

Statement 2 : Insufficient

Together : As ,Total digits ( X & Y ) less than 5 : this implies Y cant be in double digit ,so Y=5 Hence C is sufficient

As I saw the explanations and the question stem, it revealed two flaws.

(1).Non - negative integer x,y '0' is also non-negative integer.

(2). Combined total of digits of x,y mean the sum total of x and y or as stated in the explanation

Rgds, TGC ! _________________

Rgds, TGC! _____________________________________________________________________ I Assisted You => KUDOS Please _____________________________________________________________________________

Re: For nonnegative integers x and y, what is the remainder when [#permalink]
10 Aug 2013, 07:00

2

This post received KUDOS

semwal wrote:

Could somebody help with this tough question:-

If zt < -3, is z < 4? E a. z < 9 b. t < -4

thanks

From your post I perceive that you are a new bee in this forum.You have to post your question at the right place and in a right way where in you provide OA/source/difficulty level.

Rgds, TGC! _____________________________________________________________________ I Assisted You => KUDOS Please _____________________________________________________________________________

Re: For nonnegative integers x and y, what is the remainder when [#permalink]
17 Jun 2014, 02:45

I was having a lot of trouble with this one.

I could cross of the first statement as both 138/10 and 1380/10 would give the same answer, but the remainder would've been different.

For the second one I got that we have a max of 4 numbers. I could not really solve it, but I figured it was possible given the information so I picked C. (However, it was impossible with just the information from B, I sometimes just jump ahead of time-.-)

Re: For nonnegative integers x and y, what is the remainder when [#permalink]
18 Jun 2014, 05:01

2

This post received KUDOS

Expert's post

sayansarkar wrote:

what does combined total mean? That is a redundant usage...question not well formed

Source please

This means that the number of digits in x plus the number of digits in y is less than 5.

For nonnegative integers x and y, what is the remainder when x is divided by y?

(1) x/y = 13.8 --> x/y = 69/5 = 138/10 = 207/15 = ... You'll get different remainders for different x and y. Not sufficient.

(2) The numbers x and y have a combined total of less than 5 digits. Clearly insufficient.

(1)+(2) From (2) we know that the number of digits in x plus the number of digits in y is less than 5, so x and y could only be 69 and 5 (combined total of 3 digits). Sufficient.

The Stanford interview is an alumni-run interview. You give Stanford your current address and they reach out to alumni in your area to find one that can interview you...

Originally, I was supposed to have an in-person interview for Yale in New Haven, CT. However, as I mentioned in my last post about how to prepare for b-school interviews...

Interested in applying for an MBA? In the fourth and final part of our live QA series with guest expert Chioma Isiadinso, co-founder of consultancy Expartus and former admissions...