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Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8 [#permalink]

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21 Dec 2013, 22:29

Hello from the GMAT Club BumpBot!

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Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8 [#permalink]

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12 Jan 2016, 17:35

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8 [#permalink]

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09 Jun 2016, 14:04

Walkabout wrote:

For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8, the mean is how much greater than the median?

(A) 0 (B) 1 (C) n+l (D) n+2 (E) n+3

Let’s first calculate the mean (arithmetic average).

mean = sum/quantity

mean = (n + n + 1 + n + 2 + n + 4 + n + 8)/5

mean = (5n + 15)/5

mean = n + 3

Next, we determine the median. The median is the middle value when the terms are ordered from least to greatest. The terms ordered from least to greatest are as follows:

n, n + 1, n + 2, n + 4, n + 8

The median is n + 2.

Finally we are asked how much greater the mean is than the median. To determine the difference we can subtract the smaller value (the median) from the larger value (the mean) and we get:

n + 3 – (n + 2) = n + 3 – n – 2 = 1

The answer is B. _________________

Jeffrey Miller Scott Woodbury-Stewart Founder and CEO

gmatclubot

Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8
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09 Jun 2016, 14:04

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