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# For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8

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Manager
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For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8 [#permalink]  07 Dec 2012, 05:38
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Question Stats:

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For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8, the mean is how much greater than the median?

(A) 0
(B) 1
(C) n+l
(D) n+2
(E) n+3
[Reveal] Spoiler: OA
Math Expert
Joined: 02 Sep 2009
Posts: 30362
Followers: 5082

Kudos [?]: 57184 [1] , given: 8808

Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8 [#permalink]  07 Dec 2012, 05:42
1
KUDOS
Expert's post
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For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8, the mean is how much greater than the median?

(A) 0
(B) 1
(C) n+l
(D) n+2
(E) n+3

Given set in ascending order is {n, n+1, n+2, n+4, n+8}.

$$Mean=\frac{n+(n + 1)+(n + 2)+(n + 4)+(n + 8)}{5}=n+3$$;

$$Median=middle \ term=n+2$$;

$$Difference=(n+3)-(n+2)=1$$.

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Manager
Joined: 24 Oct 2012
Posts: 65
WE: Information Technology (Computer Software)
Followers: 0

Kudos [?]: 17 [1] , given: 5

Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8 [#permalink]  19 Jun 2014, 12:16
1
KUDOS
I did it similar to BrainLab .

plug in numbers, 1 for n.

mean = 1+2+3+5+9/5 = 20/5 = 4

median = 3

difference = 1

Plugin 2 for n

mean = 2+3+4+6+10/5 = 25/5 = 5

median = 4

difference = 1.
Manager
Joined: 07 Apr 2014
Posts: 147
Followers: 1

Kudos [?]: 16 [1] , given: 81

Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8 [#permalink]  11 Sep 2014, 09:32
1
KUDOS
For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8, the mean is how much greater than the median?

(A) 0
(B) 1
(C) n+l
(D) n+2
(E) n+3

if n=1 then 1, 2, 3, 5, 9

3 = median

mean = 20 / 5 = 4

difference =1
GMAT Club Legend
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Kudos [?]: 93 [0], given: 0

Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8 [#permalink]  21 Dec 2013, 21:29
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Senior Manager
Joined: 10 Mar 2013
Posts: 436
Location: Germany
Concentration: Finance, Entrepreneurship
GMAT Date: 05-27-2015
GPA: 3.88
WE: Information Technology (Consulting)
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Kudos [?]: 66 [0], given: 197

Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8 [#permalink]  19 Jun 2014, 11:07
Let's say n=2 than the set looks like this (2,3,4,6,10). The Average = 25/5=5 and the median is equal to 4 --> 5-4=1 (B)
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Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1854
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Followers: 27

Kudos [?]: 1220 [0], given: 193

Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8 [#permalink]  30 Sep 2014, 22:11
$$Mean = \frac{5n+15}{3} = n+3$$

Median = n+2

Difference = 1

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Re: For the positive numbers, n, n + 1, n + 2, n + 4, and n + 8   [#permalink] 30 Sep 2014, 22:11
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