Find all School-related info fast with the new School-Specific MBA Forum

It is currently 22 May 2015, 01:29

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

For the set of terms shown above, if y > 6 and the mean of

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
1 KUDOS received
Intern
Intern
avatar
Joined: 08 Mar 2009
Posts: 25
Followers: 1

Kudos [?]: 14 [1] , given: 13

For the set of terms shown above, if y > 6 and the mean of [#permalink] New post 02 Nov 2009, 03:08
1
This post received
KUDOS
1
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

63% (03:25) correct 37% (02:15) wrong based on 154 sessions
x, y, x + y, x - 4y, xy, 2y
For the set of terms shown above, if y > 6 and the mean of the set equals y + 3, then the median must be

A. (x+y)/2
B. y+3
C. y
D. 3y/2
E. x/3+y
[Reveal] Spoiler: OA

Last edited by Bunuel on 11 Feb 2012, 15:59, edited 1 time in total.
Edited the question and added the OA
Manager
Manager
avatar
Joined: 12 Oct 2009
Posts: 115
Followers: 2

Kudos [?]: 31 [0], given: 3

Re: Sequence [#permalink] New post 02 Nov 2009, 10:22
1
This post was
BOOKMARKED
adarsh12345 wrote:
x, y, x + y, x – 4y, xy, 2y
For the set of terms shown above, if y > 6 and the mean of the set equals y + 3, then the median must be

(x + y) 2

y + 3

y

3y/2

x /3 + y


adding up all the elements of set we get
(3x + xy)/6 = y+3 => solving this we get x=6
we have y>6 so we get
x=6,y>6,x+y >12, x-4y < -18,xy>36 and 2y >12
arranging these we get x-4y, x, y, x+y, 2y, xy

median = (y + x+y) /2 = (2y+6)/2 = y+3
will go with option 2
VP
VP
avatar
Joined: 05 Mar 2008
Posts: 1473
Followers: 11

Kudos [?]: 219 [0], given: 31

Re: Sequence [#permalink] New post 02 Nov 2009, 11:22
adarsh12345 wrote:
x, y, x + y, x – 4y, xy, 2y
For the set of terms shown above, if y > 6 and the mean of the set equals y + 3, then the median must be

(x + y) 2

y + 3

y

3y/2

x /3 + y


I get:

(x + y + x + y + x - 4y + xy + 2y)/6 = y + 3

Combine like terms and you get:

3x + xy = 6y + 18
x(3+y)=6(y+3)
3+y cancel
x = 6

Substitute 6 for x in the above equation
Also, since y>6 pick any number for y and solve. Let's say I pick a 7

the following six numbers are:
6, 7, 13, -22, 42, 14

median = (7+13)/2 = 10

my answer is B = y + 3
Manager
Manager
User avatar
Joined: 27 Oct 2011
Posts: 191
Location: United States
Concentration: Finance, Strategy
GMAT 1: Q V
GPA: 3.7
WE: Account Management (Consumer Products)
Followers: 2

Kudos [?]: 65 [0], given: 4

Re: Sequence [#permalink] New post 11 Feb 2012, 15:33
Find the average and set it equal to the y+3 then find out that x=6
then you find that y and x+y are the middle 2 numbers and sub x for 6 then you find the median number is y+3
_________________

DETERMINED TO BREAK 700!!!

Expert Post
1 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 27457
Followers: 4303

Kudos [?]: 42075 [1] , given: 5945

Re: Sequence [#permalink] New post 11 Feb 2012, 15:57
1
This post received
KUDOS
Expert's post
1
This post was
BOOKMARKED
x, y, x + y, x - 4y, xy, 2y
For the set of terms shown above, if y > 6 and the mean of the set equals y + 3, then the median must be

A. (x+y)/2
B. y+3
C. y
D. 3y/2
E. x/3+y

First of all: the median of a set with even # of terms is the average of two middle terms (when ordered in ascending/descending order).

Next, given that the mean of the set equals y+3: x+y+(x+y)+(x-4y)+xy+2y=6*(y+3) --> 3x+xy=6*(y+3) --> x(3+y)=6(y+3), notice that generally you cannot reduce by 3+y here as suggested above --> (3+y)(x-6)=0 --> x=6 or y=-3 (not a valid solution as y>6), so x=6;

Arrange the set in ascending order: {x-4y, x, y, x+y, 2y, xy} --> median=(y+x+y)/2=(2y+6)/2=y+3.

Answer: B.

Or: pick some number greater than 6 for y, let's say y=7. Then our set will be: {6, 7, 13, -22, 42, 14} --> arrange in ascending order: {-22, 6, 7, 13, 14, 42}.

Thus the median of the set is (7+13)/2=10 --> 10=7+3=y+3.

Answer: B.

Hope it helps.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

GMAT Club Premium Membership - big benefits and savings

Senior Manager
Senior Manager
User avatar
Joined: 13 Aug 2012
Posts: 464
Concentration: Marketing, Finance
GMAT 1: Q V0
GPA: 3.23
Followers: 17

Kudos [?]: 264 [0], given: 11

GMAT ToolKit User
For the set of terms shown above, if y > 6 and the mean of the s [#permalink] New post 12 Dec 2012, 23:05
x y, x + y, x – 4y, xy, 2y

\(\frac{{x + y + (x+y) + (x-4y) + xy + 2y}}{{6}} = y+3\)
\({x + y + (x+y) + (x-4y) + xy + 2y}=6(y+3)\)
\(3x + xy = 6(x+y)\)
\(x(y+3)=6(3+y)\)
\(x=6\)

Let y=7 and x=6: Set={-18, 6, 7, 13, 14, 42}
Thus, median is \frac{(7+13)}{2} = 10


A. (x + y)/2 = 13/2
B. y + 3 = 10
C. y = 7
D. (3y)/2 = 21/2
E. x/3 + y = 9

Answer: B
_________________

Impossible is nothing to God.

GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 09 Sep 2013
Posts: 4918
Followers: 298

Kudos [?]: 54 [0], given: 0

Premium Member
Re: For the set of terms shown above, if y > 6 and the mean of [#permalink] New post 14 Oct 2014, 04:37
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

Manager
Manager
User avatar
Joined: 06 Mar 2014
Posts: 237
Location: India
GMAT Date: 04-30-2015
Followers: 0

Kudos [?]: 33 [0], given: 74

Reviews Badge
Re: For the set of terms shown above, if y > 6 and the mean of [#permalink] New post 15 Apr 2015, 20:20
Bunuel wrote:
x, y, x + y, x - 4y, xy, 2y
For the set of terms shown above, if y > 6 and the mean of the set equals y + 3, then the median must be

A. (x+y)/2
B. y+3
C. y
D. 3y/2
E. x/3+y

First of all: the median of a set with even # of terms is the average of two middle terms (when ordered in ascending/descending order).

Next, given that the mean of the set equals y+3: x+y+(x+y)+(x-4y)+xy+2y=6*(y+3) --> 3x+xy=6*(y+3) --> x(3+y)=6(y+3), notice that generally you cannot reduce by 3+y here as suggested above --> (3+y)(x-6)=0 --> x=6 or y=-3 (not a valid solution as y>6), so x=6;

Arrange the set in ascending order: {x-4y, x, y, x+y, 2y, xy} --> median=(y+x+y)/2=(2y+6)/2=y+3.

Answer: B.

Or: pick some number greater than 6 for y, let's say y=7. Then our set will be: {6, 7, 13, -22, 42, 14} --> arrange in ascending order: {-22, 6, 7, 13, 14, 42}.

Thus the median of the set is (7+13)/2=10 --> 10=7+3=y+3.

Answer: B.

Hope it helps.



Hi Bunuel,

Just a small clarification needed. The highlighted portion: Is it implying that (y+3) on both sides cannot be discarded? if so, then why exactly because as per my understanding when the term in question can be ZERO, only then we must avoid cancelling it on both LHS and RHS.
Manager
Manager
User avatar
Joined: 22 Jan 2014
Posts: 115
Followers: 0

Kudos [?]: 27 [0], given: 94

Re: For the set of terms shown above, if y > 6 and the mean of [#permalink] New post 16 Apr 2015, 07:02
adarsh12345 wrote:
x, y, x + y, x - 4y, xy, 2y
For the set of terms shown above, if y > 6 and the mean of the set equals y + 3, then the median must be

A. (x+y)/2
B. y+3
C. y
D. 3y/2
E. x/3+y



assume y = 7

x would come out to be 6 (as mean is given)

median = 10

option b satisfies.
_________________

Illegitimi non carborundum.

Re: For the set of terms shown above, if y > 6 and the mean of   [#permalink] 16 Apr 2015, 07:02
    Similar topics Author Replies Last post
Similar
Topics:
9 Experts publish their posts in the topic In the graph shown above, which sector represents the $9.6 guerrero25 9 29 Oct 2013, 19:56
6 Experts publish their posts in the topic For the set of terms shown above, if y > 6 and the mean of t hogann 8 14 Oct 2009, 05:27
23 Experts publish their posts in the topic All points (x,y) that lie below the line l, shown above study 17 13 Oct 2009, 11:08
x, y, x + y, x 4y, xy, 2y For the set of terms shown ArvGMAT 7 27 Jun 2007, 20:43
for set (x,x,y,y,y,y) . Is the mean > the median??? 1) yezz 8 13 Aug 2006, 03:07
Display posts from previous: Sort by

For the set of terms shown above, if y > 6 and the mean of

  Question banks Downloads My Bookmarks Reviews Important topics  


cron

GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.