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# For the students in class A, the range of their heights is

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For the students in class A, the range of their heights is [#permalink]

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31 Jan 2008, 18:19
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

For the students in class A, the range of their heights is rcms and the greatest height is gcms. For the students in class B, the range of their height is s cms and the greatest height is hcms. Is the least height of the students in class A greater than the least height of the students in class B?

1. r<s
2. g>h
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Re: For the students in class A [#permalink]

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31 Jan 2008, 19:07
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blog wrote:
For the students in class A, the range of their heights is rcms and the greatest height is gcms. For the students in class B, the range of their height is s cms and the greatest height is hcms. Is the least height of the students in class A greater than the least height of the students in class B?

1. r<s
2. g>h

g-z=r (z is the least)

h-x=s (x is the least)

1: r<s--> pick numbers: g=15 z=4 so r=11 h=14 x=2 s=12 OR g=10 z=5 so r=5 and h=12 x=6. so s=6

We have two different plausible scenarios Insuff.

2: g=15 z=4 so r=11 h=14 x=2 so s= 12 OR g=16 z=2 so r= 14 and h=14 x=4 and s=12 Two plausible scenarios Insuff.

Together: Z must be bigger than X b/c G is bigger than H and the result of G-Z is less than H-X.

C
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Re: For the students in class A [#permalink]

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31 Jan 2008, 20:12
r=g-smallest(a) --> smallest(a) = g-r

s=h-smallest(b) --> smallest(b) = h-s

stat 1: no info about r or s, insuff to determine info for the smallest values

stat 2: no info about g or h, insuff.

together: pick numbers ... g=30, r=5, smallest(a)=25 and h=29 and r=6, smallest(b)=23.

you'll see that smallest(a) is always greater than smallest(b). So C is the answer.
Re: For the students in class A   [#permalink] 31 Jan 2008, 20:12
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