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Now, in order \(\frac{100}{n}+integer\) NOT to be an integer \(\frac{100}{n}\) must NOT be an integer, so \(n\) must NOT be a factor of 100. Hence \(n=3\).

Re: For which of the following values of n is (100+n)/n NOT an [#permalink]
24 Jul 2012, 20:41

this resolves to 100/n+1 this implies... plugging in 3 does not yield an integer.

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Re: For which of the following values of n is (100+n)/n NOT an [#permalink]
25 Jul 2012, 01:18

1

This post received KUDOS

100+n/n ==> 100/n + 1, thus, if 100/n is not an integer then the sum will not be Integer...Plugging in numbers.. .we see that 3 satisfies.. Also, 100=2*2*5*5..thus, if the numbers in the answers are not one of these individual numbers/product of these numbers, will be the answer.

Now, in order \(\frac{100}{n}+integer\) NOT to be an integer \(\frac{100}{n}\) must NOT be an integer, so \(n\) must NOT be a factor of 100. Hence \(n=3\).

Re: For which of the following values of n is (100+n)/n NOT an [#permalink]
12 Apr 2013, 07:42

2

This post received KUDOS

At first glance it was obvious to me to eliminate A, B and E answer choices. A quick way to avoid doing much mental math from that point on was to go back to smaller numbers that I knew were divisible and then make a judgement based on that. I started with 3. I stepped back to 99, a very clear multiple of 3. Add 99+3 = 102 which is clearly...not 103. We have our answer with no long division and really nothing more than identifying a clear multiple and adding 3. This allows for a solution in under 30 seconds for me. Hope this helps your speed.

Re: For which of the following values of n is (100+n)/n NOT an [#permalink]
11 May 2014, 07:29

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Re: For which of the following values of n is (100+n)/n NOT an [#permalink]
30 Jun 2014, 20:28

Thinking : Divisibility Eliminate 5 ,2 1 as these results an ineteger Solved it by applying number 3 as 103/3 = Decimal But can solve by just Divisibility rule: sum of all digits should be divisible by 3 mean 1+0+3= 4 cannot be divisble Here apply the concept then can solve more accurate:):)

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