egiles wrote:
Hi,
for x<0,
|x-1| = 1-x
\sqrt{1-(x + 1) |x-1|}
=\sqrt{1-(x + 1)(1-x)}
=\sqrt{1-1+x^2}
=\sqrt{x^2}
=|x|, again x<0
= -x
Answer (D)
Regards,
Hi!
I'm confused as why the answer isn't simply x (as opposed to-x). The absolute value of x,
when simplified, is
positive x, even if it is stated that x<0. Why do you go back and add a negative?
Thanks![/quote]
--------------------------------
What is
positive x when x is negative? What do you mean by
absolute value of x, when simplified?
Is
|-7| = -7? NOOOO!
|-7|=-(-7)=7>0!!!Absolute value is always non-negative.[/quote]
Hi EvaJager,
First, many thanks for the help you give me and others on this board. It is much appreciated.
Here is where my answer differed from yours. When I solved it, I reached this point:
= |x|
= x
Here is what you did:
= |x|
= -x
I am confused why you said the absolute value of x is -x. I thought all the absolute value of all numbers is non-negative.
Thanks again!
Eric[/quote]
-------------------------I am asking the same question again: if
x = -7, is
|-7|=-7??? NO!!!
|-7| = 7. But
x is not
7, \,\,x is
-7. What is the connection between
-7 and
7?Simply,
7 = -(-7). When
x is negative, multiplying it by
-1 it turns it into a positive number. Therefore,
|x|=-x for
x<0.You cannot write
|-7|=-7. A letter denoting a number if doesn't have a minus sign in front of it, it doesn't mean it cannot be negative.
x doesn't automatically designate a positive number. You are stating yourself that
x is negative!
Absolute value of a number expresses the distance on the number line between that number and 0. Distance between
-7 and
0 is
7.
A number
x can be negative, for example
x=-7. And
-x can be positive, if
x=-5, because
-(-5)=5.
_________________
PhD in Applied Mathematics
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