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Formula for divisors

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Senior Manager
Joined: 05 Oct 2008
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Kudos [?]: 308 [0], given: 22

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16 May 2010, 01:56
I got the following from m01. Can someone explain how 2*3*2 is derived?
Thanks.

The following formula can be used to find the number of divisors of any given number. Factor 90 ( $$90= 2*3^2*5$$ ) and then multiply the powers+1 $$2*3*2=12$$ . Therefore, divisors of 90 = 12
Senior Manager
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Kudos [?]: 616 [1] , given: 20

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16 May 2010, 02:25
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ok this is how i see it

power of 2 = 1 --> we add +1 to it --> 2
power of 3 = 2 --> we add +1 to it --> 3
power of 5 = 1 --> we add +1 to it --> 2

So we multiply all of them --> 2.3.2 = 12

And this gives us the number of factors of of 90
Re: Formula for divisors   [#permalink] 16 May 2010, 02:25
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