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# Forty percent of the employees of Company A are females, and

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Manager
Joined: 29 May 2008
Posts: 113
Followers: 1

Kudos [?]: 35 [0], given: 0

Forty percent of the employees of Company A are females, and [#permalink]  28 Aug 2009, 06:00
00:00

Difficulty:

25% (medium)

Question Stats:

77% (03:40) correct 23% (01:36) wrong based on 35 sessions
Forty percent of the employees of Company A are females, and 60% of company B are females. If 30 females employees move from Company B to company A, making the number of female employees of the two companies equal, and if the total number of employees in each company is equal, how many total make employees are there in Companies A and B together?

A. 400
B. 300
C. 200
D. 100
E. 50
[Reveal] Spoiler: OA
Manager
Joined: 20 Aug 2009
Posts: 108
Followers: 2

Kudos [?]: 54 [0], given: 31

Re: Percents [#permalink]  28 Aug 2009, 06:50
Since we know that the total number of employees in both companies is equal, let's denote it as $$x$$.
Then we have:
$$0.4x+30=0.6x-30$$
Solving for x, we get 300.
Is that right?
Manager
Joined: 25 Aug 2009
Posts: 176
Followers: 1

Kudos [?]: 68 [0], given: 12

Re: Percents [#permalink]  29 Aug 2009, 04:51
Let total employees in A = total employees in B = x

Females in A = 40% of x = 2x/5

Females in B = 60% of x = 3x/5

Now,it is given that , females in B - 30 = females in A

=> 3x/5 - 30 = 2x/5
=> x/5 = 30
=> x = 150

Hence, total employees in A & B = 2x = 2*150 = 300
Manager
Joined: 10 Jul 2009
Posts: 129
Location: Ukraine, Kyiv
Followers: 2

Kudos [?]: 63 [0], given: 60

Re: Percents [#permalink]  15 Sep 2009, 08:40
TheRob, did you mean here "...how many total make employees..." MALE? what does it mean?
what is the OA?
_________________

Never, never, never give up

Manager
Joined: 15 Sep 2009
Posts: 138
Followers: 1

Kudos [?]: 18 [0], given: 2

Re: Percents [#permalink]  16 Sep 2009, 00:40
My working :
x = total no.of employees in A/B

From the problem we can see 0.2x = 60 ; x = 300

But the combined employee strength of A + B = 600(no option)

Re: Percents   [#permalink] 16 Sep 2009, 00:40
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