Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Four couples are to select a group that consists of three [#permalink]
23 Jul 2008, 00:38

Four couples are to select a group that consists of three people from different couples. How many such groups are possible? (A) 24 (B) 28 (C) 32 (D) 36 (E) 40

P (selecting first person) = 8/8 ( can be any one) P (selecting second person) = 6/7 ( cant take spouse of first) P (selecting third person) = 4/6 (cant take spouses of first two)

for the first spot, we can pick any one person out of the 8, i.e. 8C1 = 8

for the second spot, we need to pick one person out of the remaining 6 ... not the remaining 7, since we dont want to pick the spouse of the person we selected first ... so 6C1=6

same logic for the third spot to get 4C1=4

finally, we have to divide out by 3!, since this represents the different permutations of the three spots, and we dont care about order so we end up with (8x6x4)/6 = 32

Hey everyone, today’s post focuses on the interview process. As I get ready for interviews at Kellogg and Tuck (and TheEngineerMBA ramps up for his HBS... ...