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# Four cups of milk are to be poured into a 2-cup bottle and a

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Four cups of milk are to be poured into a 2-cup bottle and a [#permalink]  01 Jul 2008, 08:26
17. Four cups of milk are to be poured into a 2-cup bottle and a 4-cup bottle. If each bottle is to be filled to the same fraction of its capacity, how many cups of milk should be poured into the 4-cup bottle?
(A) 2/3
(B) 7/3
(C) 5/2
(D) 8/3
(E) 3
Manager
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Re: mixture problem [#permalink]  01 Jul 2008, 09:05
Let x be the amount in the 4L bottle. Therefore the amount in the 2L bottle =(4-x)

since the ratios are equal
x/4 = (4-x)/2
solving,we get x=8/3
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Re: mixture problem [#permalink]  01 Jul 2008, 09:36
zeenie wrote:
Let x be the amount in the 4L bottle. Therefore the amount in the 2L bottle =(4-x)

since the ratios are equal
x/4 = (4-x)/2
solving,we get x=8/3

Why did you pick x to be the amount in the 4 cup bottle as opposed to the 2 cup bottle?
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Factorials were someone's attempt to make math look exciting!!!

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Re: mixture problem [#permalink]  01 Jul 2008, 09:59
1
KUDOS
Let x be the fraction in both the bottles.

Then, 2/x + 4/x = 4
or x = 6/4 = 3/2

Hence, cups of milk in 4 cup bottle = 4/x = 4*2/3 = 8/3

Hence, D.
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Re: mixture problem [#permalink]  01 Jul 2008, 10:38
scthakur wrote:
Let x be the fraction in both the bottles.

Then, 2/x + 4/x = 4
or x = 6/4 = 3/2

Hence, cups of milk in 4 cup bottle = 4/x = 4*2/3 = 8/3

Hence, D.

There we go. Good job. +1
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Re: mixture problem [#permalink]  01 Jul 2008, 14:10
let x be the number of cups poured into 2-cup bottle

x/2=(4-x)/4

4x=8-2x

x=4/3

4-4/3=8/3 into the 4-cup bottle
Re: mixture problem   [#permalink] 01 Jul 2008, 14:10
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