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Four fair dice are rolled together. What is the probability

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Four fair dice are rolled together. What is the probability [#permalink] New post 21 Jun 2003, 02:31
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Four fair dice are rolled together. What is the probability of having neither sixes nor fives?
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 [#permalink] New post 22 Jun 2003, 05:38
your solution please

Mine is

4/6*4/6*4/6*4/6 - all situations without 5 or 6. (2/3)^4=16/81
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 [#permalink] New post 22 Jun 2003, 06:08
ohhhhhh.........damn

i took it as three dices and so calculated (2/3)^3 :oops: :oops:
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Re: PS: PROBA-2 [#permalink] New post 11 Sep 2008, 06:28
The answer should be (4/6)^4 = 16/81
Re: PS: PROBA-2   [#permalink] 11 Sep 2008, 06:28
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Four fair dice are rolled together. What is the probability

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