four fair dice are rolled. what is the probability of having

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four fair dice are rolled. what is the probability of having [#permalink]

25 Jun 2003, 00:33

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four fair dice are rolled. what is the probability of having at least 2 threes?

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25 Jun 2003, 06:54

let us wait for other people

Four dice not three ones!

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25 Jun 2003, 13:17

Possibilities:

33** 1/6*1/6*5/6*5/6 * 4C2
333* 1/6*1/6*1/6*5/6 * 4C3
3333 1/6*1/6*1/6*1/6 * 4C4

31/6^4

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25 Jun 2003, 22:35

MBA04 wrote:

Possibilities:

33** 1/6*1/6*5/6*5/6 * 4C2
333* 1/6*1/6*1/6*5/6 * 4C3
3333 1/6*1/6*1/6*1/6 * 4C4

31/6^4

The cases are right; the sum is 171/6^4=0.1319

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25 Jun 2003, 23:20

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25 Jun 2003, 23:52

Bogdan
now these questions are more appropriate, aren't them?

[#permalink] 25 Jun 2003, 23:52

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four fair dice are rolled. what is the probability of having

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four fair dice are rolled. what is the probability of having

four fair dice are rolled. what is the probability of having

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