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# four fair dice are rolled. what is the probability of having

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four fair dice are rolled. what is the probability of having [#permalink]

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24 Jun 2003, 23:33
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four fair dice are rolled. what is the probability of having at least 2 threes?
SVP
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25 Jun 2003, 05:54
let us wait for other people

Four dice not three ones!
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25 Jun 2003, 12:17
Possibilities:

33** 1/6*1/6*5/6*5/6 * 4C2
333* 1/6*1/6*1/6*5/6 * 4C3
3333 1/6*1/6*1/6*1/6 * 4C4

31/6^4
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25 Jun 2003, 21:35
MBA04 wrote:
Possibilities:

33** 1/6*1/6*5/6*5/6 * 4C2
333* 1/6*1/6*1/6*5/6 * 4C3
3333 1/6*1/6*1/6*1/6 * 4C4

31/6^4

The cases are right; the sum is 171/6^4=0.1319
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25 Jun 2003, 22:20
SVP
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25 Jun 2003, 22:52
Bogdan
now these questions are more appropriate, aren't them?
25 Jun 2003, 22:52
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# four fair dice are rolled. what is the probability of having

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