Four female friends & four male friends will be pictured in

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Four female friends & four male friends will be pictured in [#permalink]

05 Apr 2012, 01:30

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Four female friends & four male friends will be pictured in a advertising photo. If the photographer wants to line them up in one row, with men & women alternating. How many possible arrangements may she chose?

A. 40320
B. 1680
C. 1152
D. 576
E. 70

[Reveal] Spoiler: OA

Last edited by Bunuel on 05 Apr 2012, 03:59, edited 1 time in total.

Edited the question and added the OA

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Re: Probability [#permalink]

05 Apr 2012, 01:58

Smita04 wrote:

Four female friends & four male friends will be pictured in a advertising photo. If the photographer wants to line them up in one row,with men & women alternating.How many possible arrangements may she chose?
A)40320
B)1680
C)1152
D)576
E)70

okay you got 2 ways of assigning alternate places to either male or female

hence 2

now any of the alternate 4 places can be filled by 4 male or female in 4!
similarily,
other 4 alternate places can be filled in 4!

hence required probability= 2*4!*4!=1152

hence C

Hope this helps..!!
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Re: Four female friends & four male friends will be pictured in [#permalink]

05 Apr 2012, 04:03

Smita04 wrote:

To meet the condition in the stem men and women should line up either: M-W-M-W-M-W-M-W or W-M-W-M-W-M-W-M. Now, for each of these two cases men can be arranged in 4! ways and women can be arranged also in 4! ways, hence total # of arrangements is 2*4!*4!=1,152.

Answer: C.

Hope it's clear.
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Re: Four female friends & four male friends will be pictured in [#permalink] 05 Apr 2012, 04:03

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Four female friends & four male friends will be pictured in

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Four female friends & four male friends will be pictured in

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