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fractions - springfield high (m07q15 - slightly modified)

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CEO
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fractions - springfield high (m07q15 - slightly modified) [#permalink] New post 14 Nov 2007, 13:13
At springfield high, 3/4 of males and 1/2F speak a foreign language. If there are 2/3 as many male as female students there, what fraction of the students speak a foreign language?

1/3
3/5
7/7
4/9
4/8
Senior Manager
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Re: fractions - springfield high [#permalink] New post 14 Nov 2007, 13:32
bmwhype2 wrote:
at springfield high, 3/4 of males and 1/2F speak a foreign language. If there are 2/3 as many male as female students there, what fractions of the students speal a foreign language?

1/3
3/5
7/7
4/9
4/8


M=2/3(F) assume 3 females in class then 2 males

student speaking foreign language - (3/4)males + 1/2 females

3*2/4+1*2/2=12/4=3

total sudents 3f+2m=5

3/5
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Re: fractions - springfield high [#permalink] New post 14 Nov 2007, 13:35
bmwhype2 wrote:
at springfield high, 3/4 of males and 1/2F speak a foreign language. If there are 2/3 as many male as female students there, what fractions of the students speal a foreign language?

1/3
3/5
7/7
4/9
4/8


The easiest method for me is to pick a number, which divisible by the denominator, to find the answer.

Let f=30

m = 2/3f, so m=20

Total Students
m=20
f=30
--------
50

Foreign Language Speaking Student
3/4m = 3/4(20)=15
1/2f = 1/2(30)=15
---------------------
30

What fractions of the students speak a foreign language?
30/50 = 3/5

-----------

Answer B.
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Re: fractions - springfield high [#permalink] New post 14 Nov 2007, 16:36
bmwhype2 wrote:
at springfield high, 3/4 of males and 1/2F speak a foreign language. If there are 2/3 as many male as female students there, what fractions of the students speal a foreign language?

1/3
3/5
7/7
4/9
4/8


Kaplan's picking numbers strategy makes you find speedy answer to this kind of questions.

********BMWHYPE******** you normally leave the posts open to discussion that's fine but do rarely post the OAs. Can you please kindly, regularly, post the OAs as well.

Appreciate
CEO
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 [#permalink] New post 18 Nov 2007, 03:17
OA is B.



(3/4)m=foreign speaking males
(1/2)f=foreign speaking females
m=(2/3)f

Total pop = m+f=(2/3)f+f=(5/3)f

Total foreign speaking pop = (3/4)m+(1/2)f=(3/4)(2/3)f+(1/2)f=(1/2)f+(1/2)f=f

(Tot for speak pop)/(tot pop)=f/(5f/3)=3/5
CEO
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Re: fractions - springfield high [#permalink] New post 18 Nov 2007, 03:18
Ravshonbek wrote:
bmwhype2 wrote:
at springfield high, 3/4 of males and 1/2F speak a foreign language. If there are 2/3 as many male as female students there, what fractions of the students speal a foreign language?

1/3
3/5
7/7
4/9
4/8


Kaplan's picking numbers strategy makes you find speedy answer to this kind of questions.

********BMWHYPE******** you normally leave the posts open to discussion that's fine but do rarely post the OAs. Can you please kindly, regularly, post the OAs as well.

Appreciate


i let the questions sit for a week or so, depending on when i have time to get back to reviewing the question.
Re: fractions - springfield high   [#permalink] 18 Nov 2007, 03:18
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