trivikram wrote:

M8 wrote:

Professor wrote:

M8 wrote:

From a group of 3 boys and 3 girls, 4 children are to be randomly selected. What is the probability that equal numbers of boys and girls will be selected?

A. 1/10

B. 4/9

C. 1/2

D. 3/5

E. 2/3

= 2x3c2/6c4

Prof what about this one 3C2x3C2/6C4?

But why should we multiply here?

3 boys = a, b and c

3 girls = x, y and z

no of ways 2 boys can be chosen = ab, bc, and ca

no of ways 2 girls can be chosen = xy, yz, and zx

no of ways 2boys and 2 girls can be chosen = (ab+xy), (ab+yz), ........................ and (ca+zx) = 9 ways

no of ways 4 out of 6 can be chosen = 6c4 = 15

so the prob = 9/15 = 3/5