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# From a group of 3 boys and 3 girls , 4 children are to be

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Senior Manager
Joined: 19 May 2004
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From a group of 3 boys and 3 girls , 4 children are to be [#permalink]  16 Aug 2004, 12:31
From a group of 3 boys and 3 girls , 4 children are to be randomly selected .
What is the probability that equal number of boys and girls will be selected?
Senior Manager
Joined: 25 Jul 2004
Posts: 274
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Kudos [?]: 7 [0], given: 0

I would say

(3C2 * 3C2) / 6C4

= 4/15

the top is the number of ways you can select two of the 3 boys times the number of ways you can select 2 of the 3 girls

the bottom is the number of ways you can select 4 of the six children
Senior Manager
Joined: 19 May 2004
Posts: 291
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Kudos [?]: 8 [0], given: 0

Agree. Same solution.
Joined: 31 Dec 1969
Location: India
Concentration: General Management, Strategy
GMAT 1: 710 Q49 V0
GMAT 2: 740 Q40 V50
GMAT 3: 700 Q48 V38
GPA: 3.6
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Kudos [?]: 84 [0], given: 86043

Wouldn't the correct answer be 9/15? 3C2 =3*3=9
Senior Manager
Joined: 19 May 2004
Posts: 291
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Kudos [?]: 8 [0], given: 0

Yup it's 9/15.
Sorry, I only checked SigEpUCI's way.
He made a little mistake in the final calculation.
Manager
Joined: 11 Jul 2004
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can someone please explain why is not (3c2 + 3c2) / 6C4
Senior Manager
Joined: 19 May 2004
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Use + when you need an "OR", and use * when you need an "AND".
In this question for example, you pick 2 boys AND 2 girls.
That's why you have to multiply.
Manager
Joined: 28 Jun 2004
Posts: 90
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Kudos [?]: 4 [0], given: 0

damit wrote:
can someone please explain why is not (3c2 + 3c2) / 6C4

If I am not wrong, as we want 2 boys AND 2 girls, we multiply. Addition is for "OR". Somebody correct me if I am not right.
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