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Re: From a jar containing 4 red and 2 white marbles, Lionel draws two marb [#permalink]
Lionel draws two marbles simultaneously and at random. What is the probability that he picks one marble of each color?

Doesn't GMAT questions specifically mention "with replacement" or "without replacement"

Is this question GMAT type?

WITH Replacement = 4/9
WITHOUT Replacement = 8/15
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Re: From a jar containing 4 red and 2 white marbles, Lionel draws two marb [#permalink]
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Bunuel wrote:
From a jar containing 4 red and 2 white marbles, Lionel draws two marbles simultaneously and at random. What is the probability that he picks one marble of each color?

A. 3/5
B. 8/15
C. 7/15
D. 2/5
E. 7/30

Kudos for a correct solution.


VERITAS PREP OFFICIAL SOLUTION:

Solution: 8/15. There are two paths to one of each color: Red, then White; or White, then Red. So you’ll need to calculate the probability of each sequence and add them together.

Red, then White: There’s a 4/6 probability of drawing Red first, and then there will be 2 White left to draw from the remaining 5 marbles. So that’s a probability of 2/3 * 2/5 for a total of 4/15.

White, then Red: there’s a 2/6 probability of drawing White first, at which point there would be 4 Red left to draw from the remaining 5 marbles. That’s a probability of 1/3 * 4/5 = 4/15. Add together the two probabilities to get the total probability of one of each, and you get a total of 8/15.
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Re: From a jar containing 4 red and 2 white marbles, Lionel draws two marb [#permalink]
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Bunuel wrote:
From a jar containing 4 red and 2 white marbles, Lionel draws two marbles simultaneously and at random. What is the probability that he picks one marble of each color?

A. 3/5
B. 8/15
C. 7/15
D. 2/5
E. 7/30

Kudos for a correct solution.


P(one of each color) = P(1st is red AND 2nd is white OR 1st is white AND 2nd is red)
= P(1st is red AND 2nd is white) + P(1st is white AND 2nd is red)
= [P(1st is red) x P(2nd is white)] + [P(1st is white) x P(2nd is red)]
= [4/6 x 2/5]+ [2/6 x 4/5]
= 8/30+ 8/30
= 16/30
= 8/15

Answer: B

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Re: From a jar containing 4 red and 2 white marbles, Lionel draws two marb [#permalink]
Expert Reply
Bunuel wrote:
From a jar containing 4 red and 2 white marbles, Lionel draws two marbles simultaneously and at random. What is the probability that he picks one marble of each color?

A. 3/5
B. 8/15
C. 7/15
D. 2/5
E. 7/30



Solution:

The number of ways he can choose 2 marbles is 6C2 = (6 x 5)/2 = 15. The number of ways he can choose 1 marble of each color is 4C1 x 2C1 = 4 x 2 = 8. Therefore, the probability of picking one marble of each color is 8/15.

Alternate Solution:

Lionel can choose either R-W or W-R. The probability of R-W is 4/6 x 2/5 = 8/30 = 4/15, and the probability of W-R is 2/6 x 4/5 = 8/30 = 4/15. Thus, the probability of picking one marble of each color is 4/15 + 4/15 = 8/15.

Answer: B
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Re: From a jar containing 4 red and 2 white marbles, Lionel draws two marb [#permalink]
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Re: From a jar containing 4 red and 2 white marbles, Lionel draws two marb [#permalink]
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