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Re: From a suit of 13 playing cards, a) how many hands of 5 [#permalink]
kpadma wrote:
For the question B:

I got 13C5 * 1/13 = 13C5/13.

My logic is the probability of a 5 card hand with king is 1/13.
So, the anser is as stated above.
Where is the mistake in my logic.


do not confuse combinatorics with probability.
You don't need to find any probability here.
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Re: From a suit of 13 playing cards, a) how many hands of 5 [#permalink]
stolyar wrote:
(a) 13C5
(b) 1C1*12C4 (one king+four nonkngs)


Remember that there are 4 kings in a deck.
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Re: From a suit of 13 playing cards, a) how many hands of 5 [#permalink]
I remember, but we have a suit of 13 playing cards with the only king.
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Re: From a suit of 13 playing cards, a) how many hands of 5 [#permalink]
stolyar wrote:
I remember, but we have a suit of 13 playing cards with the only king.


Ah, must quit scanning this board at 4 am....

my bad...



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