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From 'gmat "Prep [#permalink] New post 07 Nov 2009, 10:07
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

50% (00:00) correct 50% (02:54) wrong based on 2 sessions
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Re: Beans problem gmatprep [#permalink] New post 07 Nov 2009, 11:24
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first translate the problem into simpler terms.

Let total number of students be x.

therefore, we are given:

no of students who dislike beans = (2/3)x

no of students who dislike beans and sprouts = (2/3)*(3/5)x = (2/5)x
[since we are given that 3/5 of the students who dont like beans also dont like sprouts this means that 2/5 of the students who dont like beans like sprouts]

therefore, no of students who dislike beans but like sprouts = (2/3)*(2/5)x = (4/15)x

thus if we know the total number of students we can answer the question.

(1) Sufficient: it gives us what we want directly.
(2) Sufficient: 40 students like beans. this accounts for (1/3) of the students. therefore if (1/3) is 40 then total is 120.

Thus choice D is the answer.
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Re: Beans problem gmatprep [#permalink] New post 10 Nov 2009, 07:28
Nice explanation
+1 for you srihari
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Re: Beans problem gmatprep [#permalink] New post 10 Nov 2009, 07:42
zaarathelab wrote:
Nice explanation
+1 for you srihari


Thank you! :-D
_________________

Click below to check out some great tips and tricks to help you deal with problems on Remainders!
compilation-of-tips-and-tricks-to-deal-with-remainders-86714.html#p651942

Word Problems Made Easy!
1) Translating the English to Math : word-problems-made-easy-87346.html
2) 'Work' Problems Made Easy : work-word-problems-made-easy-87357.html
3) 'Distance/Speed/Time' Word Problems Made Easy : distance-speed-time-word-problems-made-easy-87481.html

Re: Beans problem gmatprep   [#permalink] 10 Nov 2009, 07:42
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