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From the consecutive integers -10 to 10 inclusive, 20

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From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 08 Jul 2012, 16:29
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From the consecutive integers -10 to 10 inclusive, 20 integers are randomly chosen with repetitions allowed. What is the least possible value of the product of the 20 integers?

A. (-10)^20
B. (-10)^10
C. 0
D. –(10)^19
E. –(10)^20
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 08 Jul 2012, 16:43
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catty2004 wrote:
From the consecutive integers -10 to 10 inclusive, 20 integers are randomly chosen with repetitions allowed. What is the least possible value of the product of the 20 integers?

A. (-10)^20
B. (-10)^10
C. 0
D. –(10)^19
E. –(10)^20


Select 10 odd number of times and -10 the remaining number of times, for example select 10 once and -10 nineteen times, then the product will be 10^1*(-10)^{19}=-10^{20}.

Answer: E.

P.S. Please read and follow: rules-for-posting-please-read-this-before-posting-133935.html
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 08 Jul 2012, 16:53
Bunuel wrote:
catty2004 wrote:
From the consecutive integers -10 to 10 inclusive, 20 integers are randomly chosen with repetitions allowed. What is the least possible value of the product of the 20 integers?

A. (-10)^20
B. (-10)^10
C. 0
D. –(10)^19
E. –(10)^20


Select 10 odd number of times and -10 the remaining number of times, for example select 10 once and -10 nineteen times, then the product will be 10^1*(-10)^{19}=-10^{20} .

Answer: E.

P.S. Please read and follow: rules-for-posting-please-read-this-before-posting-133935.html


I'm not quiet sure i understand, why choose only -10 and 10, there are other integers included in the set of -10 to 10. Also, isn't 10^1*10^(-19) = 10^(-18)?
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 08 Jul 2012, 16:57
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catty2004 wrote:
Bunuel wrote:
catty2004 wrote:
From the consecutive integers -10 to 10 inclusive, 20 integers are randomly chosen with repetitions allowed. What is the least possible value of the product of the 20 integers?

A. (-10)^20
B. (-10)^10
C. 0
D. –(10)^19
E. –(10)^20


Select 10 odd number of times and -10 the remaining number of times, for example select 10 once and -10 nineteen times, then the product will be 10^1*(-10)^{19}=-10^{20} .

Answer: E.

P.S. Please read and follow: rules-for-posting-please-read-this-before-posting-133935.html


I'm not quiet sure i understand, why choose only -10 and 10, there are other integers included in the set of -10 to 10. Also, isn't 10^1*10^(-19) = 10^(-18)?


We choose -10 and 10 because this way we get the least product (notice that -10^(20) is the smallest number among answer choices).

Also it's 10^1*(-10)^{19}=-10^{20} not 10^1*(10)^{-19}=-10^{20}.
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 08 Jul 2012, 17:35
Thanks for pointing that out!!! Silly me. But i'm still not sure, why the other answer choices are eliminated and why E is the least possible answer?? >_<
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 08 Jul 2012, 19:59
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catty2004 wrote:
From the consecutive integers -10 to 10 inclusive, 20 integers are randomly chosen with repetitions allowed. What is the least possible value of the product of the 20 integers?

A. (-10)^20
B. (-10)^10
C. 0
D. –(10)^19
E. –(10)^20



The consecutive integers from -10 to 10 are: -10, -9, -8, -7 ... -1, 0, 1, ... 9, 10

You have to select 20 integers with repetition.

So you can select all 10. The product will be 10^{20}.
or
You can select all -10. The product will be (-10)^{20} (which is essentially same as 10^{20})
or
You can select ten 1s and ten -10s. The product will be (-10)^{10}
or
You can select 0 and any other 19 numbers. The product will be 0.
or
You can select -1 and nineteen 10s. The product will be -(10)^{19}.

But how will you get - (10)^{20}?

Editing here itself - I missed out the case in which you can get - (10)^{20} (by multiplying odd number of -10 with rest of the 10s). Possibly because I mis-read the question.
'Least possible value of the product' to me implied the product that is not possible. Since all options a to d were possible, I overlooked that option (E) is possible too.

Actually the question should read 'the smallest possible value of the product' to avoid such confusion. Since -10^20 is the smallest value that can be obtained (greatest magnitude but negative), the answer is (E).
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Last edited by VeritasPrepKarishma on 09 Jul 2012, 02:00, edited 1 time in total.
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 09 Jul 2012, 00:38
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VeritasPrepKarishma wrote:
catty2004 wrote:
From the consecutive integers -10 to 10 inclusive, 20 integers are randomly chosen with repetitions allowed. What is the least possible value of the product of the 20 integers?

A. (-10)^20
B. (-10)^10
C. 0
D. –(10)^19
E. –(10)^20



The consecutive integers from -10 to 10 are: -10, -9, -8, -7 ... -1, 0, 1, ... 9, 10

You have to select 20 integers with repetition.

So you can select all 10. The product will be 10^{20}.
or
You can select all -10. The product will be (-10)^{20} (which is essentially same as 10^{20})
or
You can select ten 1s and ten -10s. The product will be (-10)^{10}
or
You can select 0 and any other 19 numbers. The product will be 0.
or
You can select -1 and nineteen 10s. The product will be -(10)^{19}.

But how will you get - (10)^{20}?
You need to select -1 and twenty 10s but you cannot select 21 numbers. You cannot have the product as negative 10^{20}.
Hence (E) is not possible
.


E is possible if you select 10 odd number of times and -10 the remaining number of times. For example:

10^1*(-10)^{19}=-10^{20} or 10^3*(-10)^{17}=-10^{20} or 10^5*(-10)^{15}=-10^{20}... or 10^{19}*(-10)^{1}=-10^{20}.

So, the answer is E.
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 09 Jul 2012, 01:54
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catty2004 wrote:
But i'm still not sure, why the other answer choices are eliminated and why E is the least possible answer?? >_<


Actually, the question means "smallest possible value of the product"

-10^{20} is the smallest value of the given 5 options. Since it is possible, so it is the answer. I guess you were thinking 'least possible' (as was I). The wording is definitely misleading.
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 09 Jul 2012, 01:58
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VeritasPrepKarishma wrote:
catty2004 wrote:
But i'm still not sure, why the other answer choices are eliminated and why E is the least possible answer?? >_<


Actually, the question means "smallest possible value of the product"

-10^{20} is the smallest value of the given 5 options. Since it is possible, so it is the answer. I guess you were thinking 'least possible' (as was I). The wording is definitely misleading.


Yes, the question means "what is the smallest possible value of the product of the 20 integers?"
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 24 Jul 2012, 20:59
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i missed out the bracket for -10^20. I was assuming that value to be positive as a negative number raised to positive power is positive. Nice problem![/edit]
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From the consecutive integers -10 to 10, inclusive.. [#permalink] New post 11 Nov 2012, 18:41
From the consecutive integers -10 to 10, inclusive 20 integers are randomly chosen with repetitions allowed. What is the least possible value of the product of 20 integers.

A. (-10)^20
B. (-10)^10
C. 0
D. -(10)^19
E. -(10)^20
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Re: From the consecutive integers -10 to 10, inclusive.. [#permalink] New post 11 Nov 2012, 18:55
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From the consecutive integers -10 to 10, inclusive 20 integers are randomly chosen with repetitions allowed. What is the least possible value of the product of 20 integers.

A. (-10)^20
B. (-10)^10
C. 0
D. -(10)^19
E. -(10)^20


The smallest possible value of the product will be negative (since it has to be smallest) with highest absolute value i.e. the number should be as left on the number line as possible.
Out of all the options, (E) is the smallest. Let's see if it is possible.
If you select all 10s and only one -10, you will get -10*(10)^{19} which is the same as -(10)^{20}. So it is possible to get the product given in (E).

Answer must be (E)

Notice that options (A) and (B) are positive.
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Re: From the consecutive integers -10 to 10, inclusive.. [#permalink] New post 12 Nov 2012, 01:21
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Bigred2008 wrote:
From the consecutive integers -10 to 10, inclusive 20 integers are randomly chosen with repetitions allowed. What is the least possible value of the product of 20 integers.

A. (-10)^20
B. (-10)^10
C. 0
D. -(10)^19
E. -(10)^20


Merging similar topics. Please refer to the solutions above.
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COLLECTION OF QUESTIONS:
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 19 Dec 2012, 00:32
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The minimum value is the biggest whole number with a negative sign.

(-10)*(10)^{19}

But this is not anywhere in the answer choice, let's manipulate: (-10)(10)^{20}=(-1)(10)(10)^{19}=-10^{20}

Answer: E
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 20 Jan 2014, 01:01
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Re: From the consecutive integers -10 to 10 inclusive, 20 [#permalink] New post 25 Aug 2014, 10:05
This question shows how important it is to carefully look at the symbols. One might be very easily deceived in thanking the question is actually saying --> (-10)^20.
Re: From the consecutive integers -10 to 10 inclusive, 20   [#permalink] 25 Aug 2014, 10:05
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