Prob of studying on day1, day 2 or day3 = 1/3
But prob of studying on day 4 is complex and I am just guessing how to calculate. But will give a shot.
There are 27 total combinations possible for first 3 days.
Out of these
in case of 2,2,2 - 4th day must be 0
in case of 1,2,2 (total 3 cases) - 4th day can be 0,1
in all other 23 cases - 4th day cane be 0,1,2
Now I am stuck!!!!!!
SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008