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G, D, I, I, F form strings such as GDIIF OR DGIFI, how many

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G, D, I, I, F form strings such as GDIIF OR DGIFI, how many [#permalink] New post 09 Oct 2003, 14:44
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G, D, I, I, F form strings such as GDIIF OR DGIFI, how many strings there are if there is at least one letter between the two I's?

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Praetorian
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Re: PS : Counting Methods ..Strings [#permalink] New post 09 Oct 2003, 15:53
praetorian123 wrote:
G, D, I, I, F form strings such as GDIIF OR DGIFI, how many strings there are if there is at least one letter between the two I's?

Thanks
Praetorian


The number of combinations using all the letters given = 5!/2! (2! for the repeating I's)

Subtract this from the combinations where I's appear together.

To get this, consider the 2 I's together to be a single letter. That way we have only 4 characters.

These can be arranged in 4! ways. In 4! combinations, the 2 I's appear together.

So, answer = 5!/2! - 4! = 60 - 24 = 36.

Amar.
Re: PS : Counting Methods ..Strings   [#permalink] 09 Oct 2003, 15:53
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G, D, I, I, F form strings such as GDIIF OR DGIFI, how many

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