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Manager
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Gambling with 4 dice, what is the probability of getting an [#permalink]
24 May 2012, 01:31
Question Stats:
48% (02:33) correct
51% (01:14) wrong based on 2 sessions
Gambling with 4 dice, what is the probability of getting an even sum? A. 3/4 B. 1/2 C. 2/3 D. 1/4 E. 1/3
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Re: Gambling with 4 dice, what is the probability of getting an [#permalink]
24 May 2012, 01:52
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cyberjadugar wrote: Gambling with 4 dice, what is the probability of getting an even sum?
A. 3/4 B. 1/2 C. 2/3 D. 1/4 E. 1/3
Looking for a one-liner answer... Even sum can be obtained in following cases: EEEE - one case. Each E can take 3 values (2, 4, or 6), so total for this case is 3^4; OOOO - one case. Each O can take 3 values (1, 3, or 5), so total for this case is 3^4; EEOO - \frac{4!}{2!2!}=6 cases (EOEO, OOEE, ...). Each E can take 3 values (2, 4, or 6) and each O can also take 3 values (1, 3, or 5), so total for this case is 6*3^2*3^2=6*3^4; Total # of outcomes when throwing 4 dice is 6^4. P=\frac{3^4+3^4+6*3^4}{6^4}=\frac{1}{2}. Answer: B. Even without any math: the probability of getting an even sum when throwing 4 dice is the same as getting an even number on one die, so it must be 1/2. Similar problem to practice: a-box-contains-100-balls-numbered-from-1-to-100-if-three-b-109279.htmlHope it helps.
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Manager
Joined: 29 Mar 2012
Posts: 245
Location: India
GMAT 1: 640 Q50 V26 GMAT 2: 660 Q50 V28 GMAT 3: 730 Q50 V38
Followers: 10
Kudos [?]:
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Re: Gambling with 4 dice, what is the probability of getting an [#permalink]
24 May 2012, 02:26
Hi Bunuel, The shortcut is perfect! Are you aware of any thread where we such approaches are discussed?Similar solution can be applied to problem like no. of cases A occurs before B in a sequence, no. of cases where A & B are together In both cases half of the total no. of cases would be the answer. Since, either A comes after B or before B, either A & B are together or separated. Regards,
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My posts: Solving Inequalities, Solving Simultaneous equations, Divisibility Rules
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Re: Gambling with 4 dice, what is the probability of getting an [#permalink]
24 May 2012, 02:30
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Re: Gambling with 4 dice, what is the probability of getting an [#permalink]
06 Feb 2013, 04:14
very hard, I want to follow this post. this is 51/51 level , I think
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Re: Gambling with 4 dice, what is the probability of getting an [#permalink]
27 Feb 2013, 05:06
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probability for EEEE to happen is
1/2*1/2*1/2*1/2=A
similarly probability for OOOO and OOEE, OEOE,...(there are 6 cases)
total 8 case
add 8 cases we have 8/A=1/2
is the result.
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Re: Gambling with 4 dice, what is the probability of getting an
[#permalink]
27 Feb 2013, 05:06
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