VeritasPrepKarishma wrote:

KitanUrchmann wrote:

Hi Everyone,

I need urgent help in solving the question attached to this mail

I anticipate your prompt responses.

Thank you.

Best regards,

KitanUrchmann

AB = Side of larger triangle - Altitude of smaller triangle = 1 - Altitude of smaller triangle

We know the relation between the side and the altitude of an equilateral triangle: Altitude = \(\frac{\sqrt{3}}{2}*Side\)

Altitude of larger triangle = \(\frac{\sqrt{3}}{2}*1\) = Side of smaller triangle

Altitude of smaller triangle = \(\frac{\sqrt{3}}{2}*\frac{\sqrt{3}}{2}*1 = \frac{3}{4}\)

AB = 1 - 3/4 = 1/4 = 0.25

See the idea what I got is for 60degree = square root 3 times 30Degree & same way for 90 degree = 2 times 30 degree. i.e. 1:root3:2....

In this case i have understood root3/2 on a larger altitude. Now to find a side opposit to 60degree in smaller altitude, we have been given only 90degree side root3/2.. so how you calculated please tell.