Geometry 7 : PS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 20 Jan 2017, 12:24

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Geometry 7

Author Message
Manager
Joined: 19 Aug 2009
Posts: 79
Followers: 1

Kudos [?]: 223 [0], given: 46

### Show Tags

02 Oct 2009, 08:57
00:00

Difficulty:

(N/A)

Question Stats:

100% (03:06) correct 0% (00:00) wrong based on 1 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Diagram not to scale
Q.
ABCD is a trapezium in which AB is parallel to DC, AD = BC, AB= 6 cm, AB=EF and DF=EC. If the two lines AF and BE are drawn so that area of ABEF is half of ABCD.
Find DF/CD.
1. 1/4
2. 1/3
3. 2/5
4.1/6
Attachments

geometry 7.JPG [ 10.89 KiB | Viewed 1336 times ]

Manager
Joined: 12 Oct 2009
Posts: 115
Followers: 2

Kudos [?]: 63 [0], given: 3

### Show Tags

13 Oct 2009, 15:00
virtualanimosity wrote:
Diagram not to scale
Q.
ABCD is a trapezium in which AB is parallel to DC, AD = BC, AB= 6 cm, AB=EF and DF=EC. If the two lines AF and BE are drawn so that area of ABEF is half of ABCD.
Find DF/CD.
1. 1/4
2. 1/3
3. 2/5
4.1/6

1/3
as per diagram and info AB=EF=6 cm and DF = EC = x(say)
then area of ABEF is 6*h (hieght) = 1/2 [1/2*( 6+6+2x)*h]
we get x= 6 so DF/ CD = 6/18 =1/3
Senior Manager
Affiliations: PMP
Joined: 13 Oct 2009
Posts: 312
Followers: 4

Kudos [?]: 161 [0], given: 37

### Show Tags

13 Oct 2009, 16:31
My Ans. is 2

1/2 (6+CD)h = 2* 1/2 (6+6)h

solving for CD, we get 18, since EF=6 and DF = EC , DF, EC must be 6 each.

hence DF/CD=6/18=1/3

matrix is always ahead of me and almost always right
_________________

Thanks, Sri
-------------------------------
keep uppp...ing the tempo...

Press +1 Kudos, if you think my post gave u a tiny tip

Manager
Joined: 12 Oct 2009
Posts: 115
Followers: 2

Kudos [?]: 63 [0], given: 3

### Show Tags

13 Oct 2009, 21:42
srini123 wrote:
My Ans. is 2

1/2 (6+CD)h = 2* 1/2 (6+6)h

solving for CD, we get 18, since EF=6 and DF = EC , DF, EC must be 6 each.

hence DF/CD=6/18=1/3

matrix is always ahead of me and almost always right

Manager
Joined: 18 Jul 2009
Posts: 169
Location: India
Schools: South Asian B-schools
Followers: 2

Kudos [?]: 98 [0], given: 37

### Show Tags

14 Oct 2009, 01:35
AB=EF=6
DF=EC=x cm

Area of ABCD = 2 ( Area of ABEF )
1/2*(6+6+x+x) = 2 ( 1/2*12*h )
x=6
thus DF/CD = 6/18 = 1/3
_________________

Bhushan S.
If you like my post....Consider it for Kudos

Re: Geometry 7   [#permalink] 14 Oct 2009, 01:35
Display posts from previous: Sort by